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Julli [10]
3 years ago
6

Where is your diaphragm located?

Physics
2 answers:
Vladimir [108]3 years ago
8 0
It's A! Below your ribcage! (: It's just underneath. You may hear the phrase "sing from your diaphragm " they're just expressing that you should sing down deep! (: Technically, it's more so a phrase because if you attempt to sing from your diaphragm there's a bunch of muscle tightening, and definitely not comfortable!
I hope all is well, and you pass! (: Good luck, rockstar!
ankoles [38]3 years ago
5 0
<span>The diaphragm is locate just under your lungs and above oyour liver</span>
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A (nonconstant) harmonic function takes its maximum value and its minimum value
AURORKA [14]

Answer:

Explanation:

Consider that F (any function) <0 .

u(x,y) is a coontinuous function in the closed interval or region R.

Let us consider a point (p,q) that is inside the region and it is a maximum point.

Then it should be must

uxx (p,q) <0 where uxx means double differentiation

and uy(p,q) >0

Since ux(p,q) = 0 = uy(p,q) where ux and uy means single differentiation with respect to x and y respectively.

Say, Maximum limits of the region is T

therefore q<T

then uy (p,q) = 0 if q<T

if q = T then

point (p,q) = (p,T) will be on the boundary of R then we claim that

uy(p,q) >0

Similarly for the minimum also it will work

3 0
3 years ago
Two parallel-plate capacitors, identical except that one has twice the plate separation of the other, are charged by the same vo
erik [133]

Answer:

The capacitor having less distance of separation has a stronger electric field.

Explanation:

The capacitors are identical and only difference between them is that one has twice the plate separation of the other. Therefore, capacitance of the given capacitors C1 and C2 is,

C1= Aε/d  and C2=Aε/2d

The charges Q1 and Q2 on the capacitors of capacitance C1 and C2 respectively, is then given by the equation,

Q1=VC1

Q1=VAε/d

Q2=VC2

Q2=VAε/2d

Therefore, the surface charge density σ1 and σ2 for the capacitors is,

σ1=Q1/A

σ1=VAε/(d*A)

σ1=Vε/d

Similarly,

σ2=Q2/A

σ2=Vε/2d

The electric field between the plates is directly proportional to the surface charge density. And so electric field is inversely proportional to the distance of separation. Therefore the capacitor whose distance of separation is less has a stronger electric field.

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8 0
3 years ago
The laboratory exercise for this chapter addresses kinematic motion. You have experienced these motions in everyday life. Instea
ki77a [65]

Answer:

A) vectors: veloicty, force

scalar:  speed, work

B)  t = 1.75 s,  C)   v = - 17 2 m / s

Explanation:

We answer each part separately

A) A vector magnitude has magnitude and direction instead a scalar magnitude has only magnitude

vector quantities: the speed of a car number is the magnitude and direction is where it goes

Force, the number is the magnitude and above that applies gives direction

Scalar magnitude: how quickly the number of the speedometer of the car

Temperature, work

B) I = 15 m height to the soil and get to calculate time = 0

        y = y₀ + v₀ t - ½ g t²

as the ball is loose its initial velocity is zero

       0 = 0 +0  - ½ g t²

       t = \sqrt{2y_o/g}

       t = \sqrt{2 \ 15/ 9.8}

       t = 1.75 s

C) the velocity to the reach the floor

      v = vo - g t

      v = 0 - g t

      v = - 9.8 1.74

       v = - 17 2 m / s

The negative signt iindicates that the speed goes down

5 0
3 years ago
How far can light travel in one year?
kumpel [21]

10 trillion km is the corrct asnwer



6 0
3 years ago
Use Snell's Law to solve the following:
azamat

Answer:

1.171

Explanation:

if n₁sinΘ₁=n₂sinΘ₂, then n₂=n₁sinΘ₁ / sinΘ₂;

n_2=\frac{1.5*sin45}{sin65}=\frac{1.5*0.707}{0.906} =1.1705

3 0
3 years ago
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