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ira [324]
3 years ago
13

3 write the three laws given by kepler.How did they help Newton to arrive at the inverse square law of gravity?​

Physics
1 answer:
stiv31 [10]3 years ago
5 0

Answer:

Kepler's laws apply: First Law: Planetary orbits are elliptical with the sun at a focus. Second Law: The radius vector from the sun to a planet sweeps equal areas in equal times. Third Law: The ratio of the square of the period of revolution and the cube of the ellipse semimajor axis is the same for all planets.

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An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal inci
VikaD [51]

Answer:

572.3 nm

Explanation:

n_{oil} = refractive index of the oil film = 1.48

t_{oil} = thickness of the oil film = 290 nm

\lambda = wavelength of the dominant color

m = order

Using the equation

2 n_{oil} t_{oil} = (m + 0.5) \lambda

For m = 0

2 (1.48) (290) = (0 + 0.5) \lambda

\lambda = 1716.8 nm

For m = 1

2 (1.48) (290) = (1 + 0.5) \lambda

\lambda = 572.3 nm

For m = 2

2 (1.48) (290) = (2 + 0.5) \lambda

\lambda = 343.4 nm

Hence the dominant color wavelength is 572.3 nm

8 0
3 years ago
What happens if you add additional,solid NaCl after the maximum has been reached?
azamat
<span>it would bond to the phosphate 

</span>
3 0
3 years ago
Read 2 more answers
How many milligrams are equivalent to 150 dekagrams?
dybincka [34]
 i believe  the answer is 1.5e+6

hope this helps!

4 0
3 years ago
Read 2 more answers
1. A small light bulb is shining light on a basketball (diameter is 23 cm or 9 inches). The light bulb is 3 m from the closest s
siniylev [52]

Answer:

The size (diameter) of the basketball's shadow on the wall is approximately 53.38 cm

Explanation:

The given parameters of the basketball are;

The diameter of the basketball = 23 cm (9 inches)

The distance of the light bulb from the closest side of the basketball = 3 m

The distance from the ball to the wall = 4 m

The distance from the light source to the center of the ball, d = 3 m + 0.23/2 m = 3.115 m

The angle the light ray makes with the edge of the ball, θ = arctan(0.115/3.115)

Therefore, the ratio of the shadow width divided by 2 to the distance from the light from the wall = 0.115/3.115

The distance from the light from the wall = 3 m + 4 m + 0.23 m = 7.23 m

Therefore;

((The width of the shadow)/2)/(The distance from the light from the wall) = 0.115/3.115

∴ ((The width of the shadow)/2)/(7.23 m) = 0.115/3.115

((The width of the shadow)/2) = 7.23 m × 0.115/3.115 = 16629/62300 m ≈ 0.2669 m = 26.69 cm

The width (diameter) of the shadow on the wall = 2 × 16629/62300 m ≈ 0.5338 m = 53.38 cm

The size (diameter) of the basketball's shadow on the wall ≈ 53.38 cm

4 0
3 years ago
A thermodynamic system undergoes a process in which its internal energy decreases by 1,477 J. If at the same time 678 J of therm
Andrews [41]

Answer:2155 J

Explanation:

Given

Change in Internal energy \Delta U=-1477 J i.e. decrease in Internal Energy

Heat added to system Q=678 J

According First law for a system

dQ=dU+dW

678=-1477+dW

dW=2155 J

Thus 2155 J of work is done by system                      

5 0
3 years ago
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