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melamori03 [73]
3 years ago
12

The laboratory exercise for this chapter addresses kinematic motion. You have experienced these motions in everyday life. Instea

d of a discussion board requiring posts in a forum, this assignment has been modified to accept your response to the following questions in this assignment. Be sure to clearly address each of the points below and show all of your work • What is the difference between a vector and a scalar quantity? • List two examples each of vector and scalar quantities • Write the due date of this assignment: Month and Day (For example, July 15 would be Month - 7. Day = 15) • For a building having a height equal to the quantity you have recorded for Day in meters in our example 15 meters), compute the time required for the ball to fall to the ground while experiencing acceleration due to gravity (g=9.8m/s) • How fast was the ball traveling when it hit the ground? Submit the kinetics Assignment by 11:59 p.m. (ET) on Monday,
Physics
1 answer:
ki77a [65]3 years ago
5 0

Answer:

A) vectors: veloicty, force

scalar:  speed, work

B)  t = 1.75 s,  C)   v = - 17 2 m / s

Explanation:

We answer each part separately

A) A vector magnitude has magnitude and direction instead a scalar magnitude has only magnitude

vector quantities: the speed of a car number is the magnitude and direction is where it goes

Force, the number is the magnitude and above that applies gives direction

Scalar magnitude: how quickly the number of the speedometer of the car

Temperature, work

B) I = 15 m height to the soil and get to calculate time = 0

        y = y₀ + v₀ t - ½ g t²

as the ball is loose its initial velocity is zero

       0 = 0 +0  - ½ g t²

       t = \sqrt{2y_o/g}

       t = \sqrt{2 \ 15/ 9.8}

       t = 1.75 s

C) the velocity to the reach the floor

      v = vo - g t

      v = 0 - g t

      v = - 9.8 1.74

       v = - 17 2 m / s

The negative signt iindicates that the speed goes down

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The electric field strength E is measured as:
soldi70 [24.7K]
The correct answer is
<span>force per unit charge.

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span>E= \frac{F}{q}
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
4 0
3 years ago
A battery is the power source for what type of current
patriot [66]

Answer: DC Current

Explanation:

Battery is a source of constant potential difference and it will create a constant voltage across any conductor

due to this constant voltage difference the current in this conductor will remain constant

So here since the voltage across the conductor is constant so we can say that current in the conductor will remain constant and hence this is known as DC current.

While for variable current in direction and magnitude is to be obtained only when the conductor is connected with AC voltage source as we know that AC voltage is variable with magnitude and direction both

A battery is the power source for DC type of current.  A battery is a source of constant potential difference that produces a constant current unlike in AC source where the voltage and hence the current changes its polarity continuously.Hence, the current produced by battery is direct current and not Alternating current.

Hope this helps........ Stay safe and have a Merry Christmas!!!!!! :D

3 0
3 years ago
Consider the following forces. (1) frictional (2) gravitational (3) tension (4) strong nuclear (5) normal (6) electroweak which
Scorpion4ik [409]

The forces listed are considered fundamental forces (2) gravitational (4) strong nuclear (6) electroweak.

Fundamental force, also called fundamental interaction, in physics, is any of the four primary forces—gravitational, electromagnetic, sturdy, and weak—that govern how gadgets or particles interact and how certain particles decay. All of the regarded forces of nature may be traced to those essential forces.

Now, physicists say they have discovered viable symptoms of a fifth essential force of nature. The findings come from studies performed at a laboratory near Chicago. The four fundamental forces govern how all of the objects and particles inside the Universe engage with each other.

The strong nuclear pressure pulled definitely and negatively charged quarks collectively to form undoubtedly charged protons and neutrally charged neutrons. The strong nuclear force also binds protons and neutrons within the nucleus of atoms. The weak nuclear force enabled complicated atoms to form through nuclear fusion.

Learn more about the fundamental forces here brainly.com/question/910002

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4 0
2 years ago
The electron beam inside an old television picture tube is 0.40 mm in diameter and carries a current of 50 μA. This electron bea
Galina-37 [17]

Answer:

A) J= 398 A/m²

B) E= 1.6×10⁶ N/C

C) P= ×10⁴ W

Explanation:

My work is in the attachment. Comment with questions or if something seems wrong with my work. (Honestly, they seem little high but it could just be the given numbers being unrealistic.) Below I have explanations of each part to match up with the image as well.

Part A:

Current density (J) is defined as the amount of current in a particular cross-sectional area. To get this, we simply need to divide the current (I) by the cross-sectional area of the electron beam tube (A).

Part B:

This one took the most work for me. I used a kinematic equation (yes they apply to electrons) to find the electric field (E). I used a modified form of the familiar: ∆d=V₀τ+aτ²/2

We can use the fact that τ= V/a, a=(qE/m), and V₀=0 here to rewrite the equation in terms of values we know and/or can look up. From there we solve for E and plug in the values.

Part C:

Power (P) is simply work (W) over time (τ). We know what τ is from before and can take W= mV²/2. Plugging these in and reducing some values gives us an equation for power as well.

5 0
3 years ago
A truck using a rope to tow a 2230-kg car accelerates from rest to 13.0 m/s in a time of 15.0s. How strong must the rope be? μk
ExtremeBDS [4]

Answer:

The rope must have a force of 10084,21 N

Explanation:

ac=ac=\frac{13}{15} \frac{m}{s}

ac=ac=\frac{13}{15} \frac{m}{s}

ac = at = \frac{13-0}{15-0}

We replaced the known information in the equation(1):

vi = Initial speed = 0, ti = initial time = 0

Known information:

at: truck acceleration(m/s2)

ac: car acceleration\frac{m}{s^{2} }

Kinematic analysis  

The car acceleration is equal to the acceleration of the truck because the truck and the car are connected by the rope.  

We apply Newton's first law to calculate the Normal force because there is no movement in the vertical direction:  

∑Fy= 0  

N-W=0  

N=W  

N=21854 N  

We replace the values of the mc and g in the equation(2):  

Wc= 2230*9.8  

Wc=21854 N  

Normal force calculation:  

Car weight calculation:  

Wc=mc*g  

mc = Car mass = 2230kg  

g = Gravity acceleration=9.8 \frac{m}{s^{2} }  

Friction force calculation (Ff):  

We have the formula to calculate the friction force:  

Ff = μk * N Equation (3)  

μk: kinetic coefficient of friction  

We know that μk = 0.373and N= 21854N , then we replaced this data in(3):  

Ff=0.373*21854

Ff=8151.54 N

Calculation of the tension force in the ro pe (T):  

We apply Newton's Second law to calculate the Normal force because there is no movement in the horizontal direction:  

∑Fx= mc*ac

We take the sense of the forces like this:  

positive to the right and negative to the left  

T-Ff=mc*ac

T=2230(\frac{13}{15} + 8151.54

T=10084,21 N

Answer: The rope must have a force of 10084,21 N  

7 0
4 years ago
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