All categories

3 years ago

The open ocean, sea floor, and coral reefs are all examples of habitats with high rates of primary production.

Physics

2 answers:

lisov135 [29]3 years ago

7 0

the answer you are seeking is false

jeka943 years ago

5 0

As the open ocean, sea floor, and coral reefs are the habitats where the plants are present in very much quantity because they can easily get their food from water, sunlight that is a source from the sun and the water is the source from open ocean. when the plants get more nourishment in this habitat, these habitat becomes the high rate primary production habitat. as the sunlight increases, the pigment known as chlorophyll also increases. This is the reason open ocean, sea floor, and coral reefs are all examples of habitats with high rates of primary production.

You might be interested in

A .422 kg coffee mug rests on a table top 0.63 m above the floor. What is the potential energy of the mug with respect to the fl

kondaur [170]

Answer:

2.61 J

Explanation:

Since potential energy U = mgy where m = mass of object, g = acceleration due to gravity = 9.8 m/s² and y = height of object above the ground.

Now for the coffee mug, m= 0.422 kg and it is 0.63 m on a table, so it is 0.63 m above the ground. Thus, y = 0.63 m.

We compute U

U = mgy

= 0.422 kg × 9.8 m/s² × 0.63 m

= 2.605 J

≅ 2.61 J

So, the potential energy of the mug with respect to the floor is 2.61 J

4 0

2 years ago

If a rock has a weight of 30 N on Earth, would its weight be more or less if it was on Jupiter (gravity on Jupiter = 25 m/s2)?

goldenfox [79]

I’m sorry this is not going as planned

8 0

3 years ago

You are riding a bicycle. If you apply a forward force of 125 N, and you and

erica [24]

Answer:

1.52g

Explanation:

Given parameters:

Force = 125N

Mass combined = 82kg

Unknown:

Acceleration of the bicycle = ?

Solution:

From Newton second law of motion suggests that:

Force = mass x acceleration

Acceleration = $\frac{force}{mass}$ = $\frac{125}{82}$ = 1.52g

8 0

3 years ago

Starting from rest, a solid sphere rolls without slipping down an incline plane. At the bottom of the incline, what does the ang

Marrrta [24]

Answer:

2/R*sqrt (g*s*sin(θ)) = w

Explanation:

Assume:

- The cylinder with mass m

- The radius of cylinder R

- Distance traveled down the slope is s

- The angular speed at bottom of slope w

- The slope of the plane θ

- Frictionless surface.

Solution:

- Using energy principle at top and bottom of the slope. The exchange of gravitational potential energy at height h, and kinetic energy at the bottom of slope.

ΔPE = ΔKE

- The change in gravitational potential energy is given as m*g*h.

- The kinetic energy of the cylinder at the bottom is given as rotational motion: 0.5*I*w^2

- Where I is the moment of inertia of the cylinder I = 0.5*m*R^2

We have:

m*g*s*sin(θ) = 0.25*m*R^2*w^2

2/R*sqrt (g*s*sin(θ)) = w

- The angular velocity depends on plane geometry θ , distance travelled down slope s, Radius of the cylinder R , and gravitational acceleration g

3 0

3 years ago

How many discovered planets are there

Allisa [31]

We have discovered 786 planets. Most of which were only recently discovered.

5 0

3 years ago