<h2>
Answer:</h2>
(a) 6.95 x 10⁻⁸ C
(b) 6.25N/C
<h2>
Explanation:</h2>
The electric field (E) on a point charge, Q, is given by;
E = k x Q / r² ---------------(i)
Where;
k = constant = 8.99 x 10⁹ N m²/C²
r = distance of the charge from a reference point.
Given from the question;
E = 10000N/C
r = 0.250m
Substitute these values into equation(i) as follows;
10000 = 8.99 x 10⁹ x Q / (0.25)²
10000 = 8.99 x 10⁹ x Q / (0.0625)
10000 = 143.84 x 10⁹ x Q
Solve for Q;
Q = 10000/(143.84 x 10⁹)
Q = 0.00695 x 10⁻⁵C
Q = 6.95 x 10⁻⁸ C
The magnitude of the charge is 6.95 x 10⁻⁸ C
(b) To get how large the field (E) will be at r = 10.0m, substitute these values including Q = 6.95 x 10⁻⁸ C into equation (i) as follows;
E = k x Q / r²
E = 8.99 x 10⁹ x 6.95 x 10⁻⁸ / 10²
E = 8.99 x 10⁹ x 6.95 x 10⁻⁸ / 100
E = 6.25N/C
Therefore, at 10.0m, the electric field will be just 6.25N/C
What is NOT one of the three primary resources that families have to reach financial goals? It is c) education
Answer:
This above a triangle that models our situation.
Explanation:
We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.
Let the component that travel in the south be the length of a.
According to the problem, the westard component is half of that so let that length be a/2.
Now we must find the angle of the wind in the South.
This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.
Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have
Now we take the arctan or inverse tan of 1/2.
You probably do this as a DC circuit which is not quite correct, but it will get you an answer. The study is a great deal more complicated.
Problem One: Secondary Power.
W = E * I
E = 10 A
I = 24V
W = 24 * 10
W = 240 Watts.
Here's the thing you have to know. These transformers are 100% efficient (or are assumed so). So whatever wattage is in the secondary, it is the same as that in the primary.
Primary Power = Secondary Power
Secondary Power = 240 Watts
Primary Power = 240 Watts
W = E * I
E = 240 volts
W = 240 watts
I = W/E = 240 / 240
I = 1 Amp. Answer Part One
Part Two
Answered above. 240 watts.
Part Three
Answered above. 240 watts.
Secondar
