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Sergio [31]
3 years ago
13

The open ocean, sea floor, and coral reefs are all examples of habitats with high rates of primary production.

Physics
2 answers:
lisov135 [29]3 years ago
7 0

the answer you are seeking is false

 



jeka943 years ago
5 0

As the open ocean, sea floor, and coral reefs are the habitats where the plants are present in very much quantity because they can easily get their food from water, sunlight that is a source from the sun and the water is the source from open ocean. when the plants get more nourishment in this habitat, these habitat becomes the high rate primary production habitat. as the sunlight increases, the pigment known as chlorophyll also increases. This is the reason open ocean, sea floor, and coral reefs are all examples of habitats with high rates of primary production.

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If fire needs oxygen to burn, where does the sun get oxygen if there is no oxygen in space?​
elena55 [62]

Answer:

through nuclear fusion

Explanation:

The burning of the sun is not chemical combustion. It is nuclear fusion. This combustion releases energy which we experience as the heat and light given off by the flame.

5 0
2 years ago
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What would a force diagram for something WHILE it is being thrown DOWNWARDS look like? <br><br> Ty
Dovator [93]

Answer:

it look the same just to tell you

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3 years ago
I'm confusion, can I please get help???
kotykmax [81]

Answer:

Anything below 7.0 is acidic, so the range would be 0 to 7.

Neutral is simply 7, in the middle of the scale.

Lastly, anything above 7.0 is basic or alkaline, so that would be 7 to 14.

Good luck, I hope this helps

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3 years ago
Two firefighters are trying to break through a door. One firefighter is heavy, and the other is light. If they run at the same s
frez [133]

Answer:

The Heavier Firefighter

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6 0
2 years ago
Un movil de masa 12Kg sobre el cual estan actuando varias fuerzas F_1=48N, F_2=60N y F_3=30N Calcular la aceleracion con la cual
Nikitich [7]

Answer:

Lamentablemente el problema está incompleto, pues no sabemos la dirección en la que se aplican las fuerzas. Por ello, voy a resolver el problema asumiendo dos casos. (abajo se puede ver una imagen donde se describe cada caso)

1) Todas las fuerzas están en la misma dirección.

Entonces la fuerza neta será la suma de las 3 fuerzas, entonces:

F = 48N + 60N + 30N = 138N

Y por la segunda ley de Newton sabemos que:

F = m*a

fuerza igual a masa por aceleración.

Entonces la aceleración está dada por:

a = F/m = 138N/12kg = 11.5 m/s^2

2) Segundo caso, suponemos que F1 es opuesta a F2 y F3

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F = F2 + F3 - F1 = 60N + 30N - 48N = 42N

En este caso, la aceleración será:

a = 42N/12kg = 3.5 m/s^2

7 0
2 years ago
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