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3 years ago

How is displacement different from distance?

Physics

2 answers:

Anni [7]3 years ago

5 0

Answer:

i do belive its C

Explanation:

i remeber this question from somewhere also it makes the most sense

Bas_tet [7]3 years ago

4 0

I honestly think the answer is c because it motions if for the path

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The energy of random atomic and molecular motion is called.

Vanyuwa [196]

Energy of a random atomic and molecular is called molecules energy

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2 years ago

which statement is true about the atomic mass? a. it is never greater than the atomic number b. it always equal the atomic numbe

Shtirlitz [24]

D. it can be greater than the atomic number

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3 years ago

Read 2 more answers

A 10.0 Ω lightbulb is connected to a 12.0 V battery. (a) What current flows through the bulb? (b) What is the power of the bulb?

andreev551 [17]

The current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

<h3>What current flows through the bulb as well as the power of the bulb?</h3>

From ohm's law; V = I × R

Where V is the voltage, I is the current and R is the resistance.

Also, Power is expressed as; P = V × I

Where V is voltage and I is current.

Given that;

Resistance R = 10.0 ohms
Voltage V = 12.0V
Current I = ?
Power P = ?

First, we determine the current flow through the bulb.

V = I × R

12.0V = I × 10.0 ohms

I = 12.0 ÷ 10.0

I = 1.2A

Next, we determine the power of the bulb.

P = V × I

P = 12.0V × 1.2A

P = 14.4 Watts

Therefore, the current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

Learn more about Ohm's law here: brainly.com/question/12948166

#SPJ1

6 0

1 year ago

A car traveling in a straight line has a velocity of 5.0 m/s. After an acceleration of 0.75 m/s/s, the cars velocity is 8.0. In

Bogdan [553]

Vs - velocity on beginning
ve - velocity on ending. You've got:
$v_s = 5 \frac{m}{s} \\ v_e=8 \frac{m}{s} \\ \hbox{Then:} \\ \Delta v=v_e - v_s = 8 \frac{m}{s} - 5\frac{m}{s}=3 \frac{m}{s} \\ a=0,75 \frac{m}{s^2} \\ \hbox{And from formula:} \\ a=\frac{\Delta v}{\Delta t} \qquad \Rightarrow \qquad \Delta t= \frac{\Delta v}{a} \\ \hbox{Substitute:} \\ \Delta t=\frac{3\frac{m}{s}}{0,75 \frac{m}{s^2}}= \frac{3}{\frac{3}{4}} s= 3 \cdot \frac{4}{3} s= 4 s$
So he needed 4 second.

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3 years ago

Electrical current is defined as

Dmitry_Shevchenko [17]

Explanation:

The flow of electrical charge per unit time

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3 years ago