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shepuryov [24]
2 years ago
7

What is the ph of 0.05l of hand soap? is it acidic or basic?

Chemistry
1 answer:
kari74 [83]2 years ago
7 0
Hand soap It’s a a basicccc
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It is important to understand the differences between chemical and physical changes. Chemical changes result in new substances,
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Answer:

Melting of ice

Explanation:

A physical change is one in which just the physical properties of the matter is altered. Most phase changes reaction falls under this type of change.

  • Examples are boiling, melting, freezing, condensation, sublimation, magnetization of metals, breaking glass, cutting wood.
  1. No new kinds of matter is formed.
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At what phase of mitosis are two separate nuclei are formed as nuclear membranes form around
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Probably telophase because for the difference in the nuclear membrane
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Which statement best describes the pH of pure water?
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The pH of pure water is neutral because the concentration of hydronium ions equals that of hydroxide ions.

Answer: Option A

<u>Explanation:</u>

Water is one of the most important constituents of living being. It is said that there is no life without water. So that water need to neutral in nature to save life. Pure water is composed of hydronium H^{+} and hydroxide \left(O H^{-}\right) ions. It is known that hydronium ions are acidic in nature with concentration of 1 \times 10^{-7} \mathrm{M} / \mathrm{L}.

Similarly, the hydroxide ions which are basic in nature will be in same concentration as that of hydronium ions. So, as the concentration of basic and acidic elements are equal with the same strength of pH, the combination of these ions lead to formation of pure water with the pH being neutral.

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Which of the following measurements is equal to 2.3 dL?
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What are the following measurements?
6 0
3 years ago
What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances
belka [17]

The given question is incomplete. The complete question is:What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances.

Isotope                    mass amu        Relative abundance

1                                77.9                     14.4

2                               81.9                     14.3

3                               85.9                      71.3

Express your answer to three significant figures and include the appropriate units.

Answer: 84.2 amu

Explanation:

Mass of isotope 1 = 77.9  

% abundance of isotope 1 = 14.4% = \frac{14.4}{100}=0.144

Mass of isotope 2 = 81.9

% abundance of isotope 2 = 14.3% = \frac{14.3}{100}=0.143

Mass of isotope 3 = 85.9

% abundance of isotope 2 = 71.3% = \frac{71.3}{100}=0.713

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(77.9\times 0.144)+(81.9\times 0.143)+(85.9\times 0.713)]

A=84.2amu

Therefore, the average atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances is 84.2 amu

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