Question

5. What is the final "Celsius" temperature if 2.40 L of gas at 30.5 C is cooled until the volume reaches 1.00 L at constant pressure?

Answer 1

Answer:

Final temperature of the gas = -146.63 °C

Explanation:

At constant pressure, volume and temperature of the gases are related as:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Where,

V1 = Initial volume = 1.00 L

V2 = Final volume = 2.40 L

T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K

Now, substitute the values in the above equation,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{2.40\;L}{303.65}=\frac{1.00\;L}{T_2}$

$T_2=\frac{1.00\times 303.65}{2.40}$

T2 = 126.52 K

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

T( °C) = T(K) - 273.15

          = 126.52 - 273.15 = -146.63 °C