The change in entropy of 20.0 moles of ideal monatomic constant volume gas as it changes from an initial temperature 300 K to it

Question

3 years ago

15

s final temperature is 200 J/K. What is the final temperature of the gas

1 answer:

Gre4nikov [31] · Answer 1 · 2022-08-24T08:21:30+03:00

Answer:

668.9K is the final temperature

Explanation:

The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:

ΔS = n*Cv*ln (T2/T1)

<em>Where ΔS is change in entropy = 200J/K</em>

<em>n are moles = 20.0mol</em>

Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)

T2 is final Temperature and T1 initial temperature = 300K

Replacing:

ΔS = n*Cv*ln (T2/T1)

200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)

0.80186 = ln (T2/300K)

2.23 = T2 / 300K

<h3>668.9K is the final temperature</h3>