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frozen [14]
3 years ago
15

The change in entropy of 20.0 moles of ideal monatomic constant volume gas as it changes from an initial temperature 300 K to it

s final temperature is 200 J/K. What is the final temperature of the gas
Chemistry
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

668.9K is the final temperature

Explanation:

The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:

ΔS = n*Cv*ln (T2/T1)

<em>Where ΔS is change in entropy = 200J/K</em>

<em>n are moles = 20.0mol</em>

Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)

T2 is final Temperature and T1 initial temperature = 300K

Replacing:

ΔS = n*Cv*ln (T2/T1)

200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)

0.80186 = ln (T2/300K)

2.23 = T2 / 300K

<h3>668.9K is the final temperature</h3>
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How many grams of sulfur must be burned to give 100.0 g of So2
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50 g of S are needed

Explanation:

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S(s) + O₂ (g) →  SO₂ (g)

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4 0
3 years ago
Please help me
Wittaler [7]

Answer:

pH = 6.999

The solution is acidic.

Explanation:

HBr is a strong acid, a very strong one.

In water, this acid is totally dissociated.

HBr + H₂O  →  H₃O⁺  +  Br⁻

We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

[H⁺] = [Br⁻] + [OH⁻]

All the protons come from the bromide and the OH⁻ that come from water.

We can also think [OH⁻] = Kw / [H⁺] so:

[H⁺] = [Br⁻] + Kw / [H⁺]

Now, our unknown is [H⁺]

[H⁺] =  7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]

[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) /  [H⁺]

This is quadratic equation:  [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴

a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴

(-b +- √(b² - 4ac) / (2a)

[H⁺] = 1.000038751×10⁻⁷

- log [H⁺] = pH → 6.999

A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.

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Answer:

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