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frozen [14]
2 years ago
15

The change in entropy of 20.0 moles of ideal monatomic constant volume gas as it changes from an initial temperature 300 K to it

s final temperature is 200 J/K. What is the final temperature of the gas
Chemistry
1 answer:
Gre4nikov [31]2 years ago
7 0

Answer:

668.9K is the final temperature

Explanation:

The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:

ΔS = n*Cv*ln (T2/T1)

<em>Where ΔS is change in entropy = 200J/K</em>

<em>n are moles = 20.0mol</em>

Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)

T2 is final Temperature and T1 initial temperature = 300K

Replacing:

ΔS = n*Cv*ln (T2/T1)

200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)

0.80186 = ln (T2/300K)

2.23 = T2 / 300K

<h3>668.9K is the final temperature</h3>
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Read 2 more answers
A sample of water at 100°C is converted to steam after absorbing 820 kJ of heat. How grams of H2O are contained in the sample? A
Varvara68 [4.7K]
Since water is already at 100<span>°C all the energy is used to evaporate it. 
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N= \frac{820}{41} =20 mol
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7 0
3 years ago
How many Mg atoms are presented in 3.00 moles of MgCl2
ella [17]

Answer:

1.81 x 10²⁴ atoms

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To find the number of atoms in the given number of moles, we need to understand that every substance contains the Avogadro's number of particles.

More appropriately, a mole of any substance will contain the Avogadro's number of particles which is 6.02 x 10²³ atoms

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3 years ago
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