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LiRa [457]
3 years ago
7

Two tuning forks are sounded at the same time. which tuning forks will give rise to a beat frequency of 30 hz when sounded toget

her with a 270 hz tuning fork?
Physics
1 answer:
SOVA2 [1]3 years ago
6 0

Answer:

300 Hz and 240 Hz

Explanation:

Beat frequency formed by the tuning fork is given by :

f_{beat}=f_1\pm f_2

Here, the beat frequency, f_{beat}=30\ Hz

The frequency of a tuning fork, f_2=270\ Hz

If f_{beat}=f_1+f_2

f_1=f_{beat}-f_2

f_1=30-270

f_1=240\ Hz

If f_{beat}=f_1-f_2

f_1=f_{beat}+f_2

f_1=30+270

f_1=300\ Hz

So, the tuning forks will give rise to a beat frequency are 240 Hz and 300 Hz. Hence, this is the required solution.

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A Michelson interferometer uses light from a sodium lamp. Sodium atoms emit light having wavelengths 589.0 nm and 589.6 nm. The
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The distance mirror M2 must be moved so that one wavelength has produced one more new maxima than the other wavelength is;

<u><em>L = 57.88 mm</em></u>

<u><em /></u>

We are given;

Wavelength 1; λ₁ = 589 nm = 589 × 10⁻⁹ m

Wavelength 2; λ₂ = 589.6 nm = 589.6 × 10⁻⁹ m

We are told that L₁ = L₂. Thus, we will adopt L.

Formula for the number of bright fringe shift is;

m = 2L/λ

Thus;

For Wavelength 1;

m₁ = 2L/(589 × 10⁻⁹)

For wavelength 2;

m₂ = 2L/(589.6)

Now, we are told that one wavelength must have produced one more new maxima than the other wavelength. Thus;

m₁ - m₂ = 2

Plugging in the values of m₁ and m₂ gives;

(2L/589) - (2L/589.6) = 2

divide through by 2 to get;

L[(1/589) - (1/589.6)] = 1

L(1.728 × 10⁻⁶) = 1

L = 1/(1.728 × 10⁻⁶)

L = 578790.67 nm

L = 57.88 mm

Read more at; brainly.com/question/17161594

8 0
2 years ago
A cyclist rides at 6.20 m/s through a intersection. A stationary car begins to
Xelga [282]

Answer:

The width of the intersection is 20 meters

Explanation:

The speed with which the cyclist is riding, v₁ = 6.20 m/s

The rate at which the car starts to accelerate, a = 3.844 m/s²

The initial velocity of the car = The car is stationary at the start = 0 m/s

The time at which the cyclist and the car reach the other side of the intersection = The same time;

Let 't' represent the time at which the cyclist and the car both reach the other side of the intersection, we have;

The distance travelled by the cyclist = The distance traveled by the car

∴ v₁ × t = 1/2 × a × t²

Plugging in the values for 'v₁', and 'a' in the above equation, we get;

6.20 × t = 1/2 × 3.844 × t²

∴ 1.922·t² - 6.20·t = 0

∴ t·(1.922·t - 6.20) = 0

t = 0, or t = 6.20/1.922 = 100/31

The time at which the cyclist and the car both reach the other side of the intersection, t = 100/31 seconds

The with of the intersection, w = v₁ × t

∴ w = 6.20 × 100/31 = 100/5 = 20

The width of the intersection, w = 20 meters.

8 0
3 years ago
What is the speed of a bobsled whose distance-time graph indicates that it traveled 119m in 27s
BaLLatris [955]
4ms I'm just guessing by the way

3 0
3 years ago
Question 5 of 10
muminat
The correct answer to this question is D
5 0
3 years ago
The path of the sun on the celestial sphere is called.
Ede4ka [16]

Answer:

Ecliptic

Explanation:

The path the sun, moon, and planets take across the sky as seen from Earth. It defines the plane of the Earth's orbit around the sun. The name "Ecliptic" comes from the fact that eclipses take place along this line.

7 0
3 years ago
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