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timama [110]
4 years ago
5

Please help.

Physics
2 answers:
LenKa [72]4 years ago
7 0
Mu wildest guess is c 1500
maw [93]4 years ago
4 0

Answer:

B. 5000

Explanation:

The tow rope should be strong enough so that it can overcome the frictional force and pull pallet without breaking. In question following data is given:

                          Weight of pallet = W = 6000lbs  

                          Coefficient of friction = uK = 0.42

The tow rope required to pull pallet = (Weight of pallet) (Coefficient of friction)

                                                               = (W)( uK)

                                                                = (6000)(0.42)

                                                                 = 2520 lbs

5000lbs is higher value than 2520lbs. Hence, if we will use 5000lbs tow rope it can easily pull the pallet.

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<h2>Answer:</h2>

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P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}(\frac{1+cos(2\omega t)}{2} )dt \\\\P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}[\frac{1}{2}+\frac{cos(2\omega t)}{2}]dt \\\\P=\frac{v_{m}i_{m}}{T}[\frac{1}{2}(t)\right|_0^T +\frac{sin(2\omega t)}{4\omega} \right|_0^T] \\ \\ P=\frac{v_{m}i_{m}}{2T}[(t)\right|_0^T +\frac{sin(2\omega t)}{2\omega} \right|_0^T] \\ \\ P=\frac{v_{m}i_{m}}{2}

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3 years ago
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Answer:

Explanation:

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dv / dt = k ( 160 - v )

dv / ( 160 - v ) = kdt

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Putting the values , we have

c = ln 160

ln ( 160 - v ) = kt + ln 160

ln ( 160 - v / 160 ) = kt

(160 - v ) / 160 = e^{kt}

1 - v / 160 = e^{kt }

v / 160 = 1 - e^{kt }

v = 160 ( 1 - e^{kt } )

differentiating ,

dv / dt = - 160k e^{kt }

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given when t = 0 , a = 280

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5 0
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Answer:

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heat input = 5000 / .2466

= 20275.75 J .

HEAT EXTRACED = 20275.75 J.

3 0
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