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3 years ago

What is the answer of a ?

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

4 0

Answer:

Step-by-step explanation:

Use the cosine law (look at the picture).

We have:

$a=a\\b=4\\c=3\\\gamma=32^o$

$a^2=4^2+3^2-2(4)(3)\cos32^o$

$\cos32^o\approx0.848$ → look at the second picture

$a^2=16+9-24(0.848)\\\\a^2=25-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2$

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A sample of 100 roller coaters examines the relationship between top speed (response) and max drop (explanatory). Based off of t

vekshin1

Answer:

From the plot it is clear that assumption 1 and 2 are violated. That is, the assumption of equal variance ( homoscedasticity) and there aren't any outliers.

Step-by-step explanation:

Both variables are quantitative and The relationship is linear have not been violated.

6 0

2 years ago

Use the given information to answer the following questions. center (3, -9, 3), radius 5 (a) Find an equation of the sphere with

lianna [129]

Answer: The equation of the sphere with the center and radius

$x^{2} +y^{2} +z^{2}-6 x+18 y-6 z+74=0$

b) The intersection of this sphere with the y z-plane the x- co-ordinate

is zero(i.e., x = 0 )

Step-by-step explanation:

a) The equation of the sphere having center (h,k,l) and radius r is

$(x-h)^{2} +(y-k)^2+(z-l)^2 = r^2$

Given center of the sphere (3, -9, 3) and radius 5

$(x-3)^{2}+(y+9)^2+(z-3)^2 = 5^2$

on simplification , we get solution

$x^{2} -6 x+9+y^{2} +18 y+81+z^{2}-6 z+9=25$

$x^{2} +y^{2} +z^{2}-6 x+18 y-6 z+74=0$

Final answer :-

$x^{2} +y^{2} +z^{2}-6 x+18 y-6 z+74=0$

b) The intersection of this sphere with the y z-plane the x- co-ordinate

is zero(i.e., x = 0 )

$y^{2} +z^{2}+18 y-6 z+74=0$

7 0

3 years ago

What is the distance between the points (12 , -17) and (-12 , -17) in the coordinate plane?

romanna [79]

I think it’s 0 units

6 0

2 years ago

WILL MARK FIRST CORRECT ANSWER BRAINLIEST

exis [7]

Answer:

Step-by-step explanation:

Hope this helps!

7 0

3 years ago

The current in a circuit element is i(t) = 3(1 - e-2t) A when t ≥ 0 and i(t) = 0 when t < 0. The total charge that has entere

lesantik [10]

Answer:

A=-3/2

B=3

c=3/2

a=-2

Step-by-step explanation:

Knowing that for $t>0$ $i(t)=2\left(1-e^{-2t}\right) A$ , $i(t)=0$ when t<0 and using the definition of charge

$q(t)=\int_{-\infty}^0i(t')dt'+\int_0^t i(t')dt'=0+\int_0^t i(t')dt'$

The first term corresponds to q(0), the charge accumulated before t=0, in this case it luckily gives zero so we don't have to worry about it.

Let's proceed and integrate $i(t)$ then when t>0

$i(t)=3\int_0^t \left[ \int_0^tdt'-\inte_0^t e^{-2t'}dt' \right]dt'=3\left[ t+\frac{1}{2}\left( e^{-2t}-1 \right) \right]=3t+\frac{3}{2}e^{-2t}-\frac{3}{2}\,\, C$

It is clear that:

A=-3/2

B=3

c=3/2

a=-2

4 0

2 years ago