The Number of moles required for MTBE is 2 as per molarity based chemistry theories.
- A flammable liquid with a distinct, unpleasant smell is called methyl tert-butyl ether (MTBE).
- Since the 1980s, it has been added to unleaded gasoline as a fuel additive to promote more effective burning.
- It is created by mixing chemicals like isobutylene and methanol. Gallstones can be removed with MTBE as well.
- In this type of treatment, surgically inserted special tubes are used to deliver MTBE directly to the gall bladders of the patients.
- Methyl tert-butyl ether is a colorless liquid with a distinct anesthetic-like smell. Vapors are narcotic and heavier than air. 131 °F boiling point. 18 °F is the flash point.
- It is miscible in water and less dense than water. Boosts the octane of gasoline.
- Therefore it has 2 moles of oxygen.
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OK now that’s a lot to ask for but if you want someone to actually do that you’re gonna need a lot more points
Answer:
When SO
2
is passed through an acidified solution of H
2
S, sulphur is precipitated out according to the reaction.
2H
2
S+SO
2
→2H
2
O+3S
The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. The masses (in mg) that remains after t years A=150/2^t/30yrs
<h3>what do you mean by half-life?</h3>
A substance's half-life is the amount of time it takes for half of it to decompose.
<h3>What is a half-life example?</h3>
Half-life is the length of time it takes for half of an unstable nucleus to go through its decay process. A radioactive element's half-life decay time varies depending on the element. For instance, carbon-10 has a half-life of only 19 seconds, making it impossible to discover in nature. On the other hand, uranium-233 has a half-life of almost 160000 years.
When n half-lives have passed, the formula for estimating the amount still left is:-
A=A°/2^n
where,
A=initial amount
A°=remaining amount
n=t/t_{1/2}
A=150/2^t/30yrs
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The percentage of excess air used during combustion process of ethane will be 37 %.
Burning, also known as combustion, would be a high-temperature highly exothermic chemical process that occurs when an oxidant, typically atmospheric oxygen, interacts with a fuel to generate oxidized, frequently gaseous products in a mixture known as smoke.
Calculation of percentage of air .
Mair=Mair/Rin
+ 
÷ 
+ +
33 . 3.25(1-x) + 28 × 13.16(1-x) ÷ 33 × 3.25(1-x) + 28 × 13.16(1-x). + 30.1
= 176/176+8
X= 0.37
0.37 × 100
X= 37%
Therefore, the percentage of excess air used during combustion process of ethane will be 37 %.
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