Question

a plane flies 400 km east from city a to city b in 45.0 min and then 980 km south from city b to city c in 1.50 h. (assume the x axis points east and the y axis points north.) (a) in magnitude-angle notation, what is the plane's displacement for the total trip?

Answer 1

The plane's displacement for the total trip is, -63.2°.

Velocity, v = x/t

Vx = 459 km/2.483 hr = 184.8 km/h

Vy = -909 km/2.483 hr = - 366 km/hr

Magnitude, v =sqrt(Vx^2 + Vy^2) = 410 km/hr

Direction, theta = arctan (-366/184.8) = - 63.2°

What is in plane displacement?

Double symmetrical illumination of the object, successively for each illumination direction, is used to measure in-plane displacement as the loading is gradually increased. The impact response of structures is significantly impacted by the in-plane displacements at the supports.

This is so that axial membrane forces along the beam's center line can be introduced by the development of geometrical modifications. Given that the double-hull specimen should have been strengthened by sturdy brackets at the boundaries of the outer and inner plates, this anomaly is likely the result of insufficient experimental restrictions (top and bottom plates).

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