General relativity was first proposed by Einstein.
Hope this helps! Let me know if you need the definition :)
Answer:
(a) Z = 48.3 Ω
(b) cos ∅ = 0.455
(c) Irms = 10.35 A
(d) C = 74.02 μF
(e) Irms = 4.44 A
Explanation:
Power (P) = 2.36 kW
Frequency (f) = 50 Hz
RMS Voltage (Vrms) = 500 V
Resistance (R) = 22 Ω
Inductive Reactance (XL) = 43 Ω
(a) to calculate the total impedance, use the formula:
Z = √(R² + XL²)
= √((22)² + (43)²)
= √2333
Z = 48.3 Ω
(b) To calculate the plant's power factor, we will use the formula:
cos ∅ = R/Z
= 22/48.3
cos ∅ = 0.455
(c) To calculate the RMS current used by the plant, divide the RMS voltage value by the impedance of the plant.
Irms = Vrms/Z
= 500/48.3
Irms = 10.35 A
(d) For the power factor to become unity, the inductive reactance must be equal to the capacitive reactance i.e. Xc = XL
Xc = XL
1/(2πfC) = XL
1/(2πfXL) = C
C = 1/(2π*50*43)
= 7.402 x 10⁻⁵
C = 74.02 μF
(e) P = Vrms*Irms*cos∅
Irms = P/Vrms*cos∅
= 2.22 x 10³/500*1
Irms = 4.44 A
Answer:
It is<em> impossible</em> to construct a machine which produces the <em>work output greater than the work input.</em>
Let us consider the II law of thermodynamics.
According to Kelvin Plank's statement any engine/machine does not give hundred percent efficiency. And violating the PMM-II(Perpetual motion of machine II kind), Always some amount of energy transferred to the sink or surroundings.
Therefore
W(ouput) = Q₁-Q₂
There are many reasons to lower the work output, just for an example friction between the mating parts reduces the work output.
Because Mars is too far away for its gravitational pull to affect us, in addition Earths gravitational pull is greater than Mars anyways.
Answer:
When you jump off a train, you jump off a certain height and your downwards (vertical) velocity is zero. But your forward (horizontal) velocity is not. You will hit the ground on split second with your horizontal velocity practically the same as the train.
Explanation:
you be in serious injury.
