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sammy [17]
3 years ago
13

The greater the mass of an object? I’ll give brainliest!*

Physics
1 answer:
liraira [26]3 years ago
6 0

between B and C im thinking its more C though

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A circuit contains a 305 ohm resistor, a 1.1 micro Farad capacitor, and a 42 mH inductor. At resonance, the impedance is determi
r-ruslan [8.4K]

Answer:

The resistance of the inductor at resonance is 258.76 ohms.

Explanation:

Given;

resistance of the resistor, R = 305 ohm

capacitance of the capacitor, C = 1.1 μF = 1.1 x 10⁻⁶ F

inductance of the inductor, L = 42 mH = 42 x 10⁻³ H = 0.042 H

At resonance the inductive reactance is equal to capacitive reactance.

\omega L = \frac{1}{\omega C}\\\\2\pi F_0 L =  \frac{1}{2\pi F_0 C}\\\\F_0 = \frac{1}{2\pi\sqrt{LC} }

Where;

F₀ is the resonance frequency

F_0 = \frac{1}{2\pi\sqrt{LC} } \\\\F_0 = \frac{1}{2\pi\sqrt{(0.024)(1.1*10^{-6})} }\\\\F_0 =980.4 \ Hz

The inductive reactance is given by;

X_l = 2\pi F_0 L\\\\X_l = 2\pi (980.4)(0.042) \\\\X_l = 258.76 \ ohms

Therefore, the resistance of the inductor at resonance is 258.76 ohms.

5 0
3 years ago
A 5 N force is applied to a 3 kg ball to change its velocity from 9 m/s to 3 m/s. What is the impulse on the ball ?
nika2105 [10]
So, first the formula of Impulse is
I = force * time
We have force but no time.
Then, find time.
Next find acceleration,
F = mass * acceleration
5 = 3 * a
1.67 m/s^2
Next find time,
Acceleration = change in velocity / time
Change in velocity is velocity final - velocity initial
1.67 = 3 - 9 / time
Time = 3.6 s (round to 2 s.f.)
Lastly,
Impulse = force * time
Impulse = 5 * 3.6
Impulse is 18 Ns
3 0
3 years ago
Consider the situation||: A child pulls a sled by a rope across the lawn at a constant speed. Of the forces listed, identify whi
Mice21 [21]

Answer:

Gravitational

Tension

Normal

Friction.

Explanation:

The forces acting on the sled are:

Tension: the tension from the rope, this is the force that "moves" the sled.

Friction: kinetic friction between the sled and the ground as the sled moves.

There are another two forces that also act on the sled, but that "has no effect"

Gravitational force: This force pulls the sled down, against the floor.

Normal force: This force "opposes" to the gravitational one, so they cancel each other.

These two forces cancel each other, so they have no direct impact on the movement of the sled. BUT, the friction force depends on the weight of the moving object, and the weight of the moving object depends on the gravitational force, so we need gravitational force in order to have friction force.

Then we can conclude that the forces acting on the sled are:

Gravitational

Tension

Normal

Friction.

6 0
3 years ago
How do scientists measure the amount of carbon dioxide in the atmosphere for dates prior to the 1955?
Debora [2.8K]

The scientists measured the amount of carbon dioxide in the atmosphere for dates prior to 1955, From air bubbles in glacial ice cores.

Almost 412 parts per million (ppm) of carbon dioxide are currently present in the Earth's atmosphere, and that number is increasing. This indicates an 11 per cent increase since 2000, when the concentration was close to 370 ppm, and a 47 per cent increase since the start of the Industrial Age when the concentration was close to 280 ppm. Most of the time, scientists do not consider Carbon dioxide as a percentage of the earth's atmosphere. It helps to picture a million equal pieces of an atmospheric gas sample.

Learn more about carbon dioxide here:

brainly.com/question/3049557

#SPJ4

6 0
1 year ago
An electron is located in an electric field of magnitude 600 Newton's per coulomb. What is the magnitude of the electrostatic fo
qaws [65]

Answer:  

force on electron will be equal to 9.6\times 10^{-17}N

Explanation:

We have given magnitude of electric field E = 600 N/C

Charge on electron e=1.6\times 10^{-19}C

We have to find the electric force on the electron

Force in electric field is equal to F=qE, here q is charge and E is electric field

So force will be equal to F=1.6\times 10^{-19}\times 600=960\times 10^{-19}=9.6\times 10^{-17}N

So force on electron will be equal to 9.6\times 10^{-17}N

4 0
3 years ago
Read 2 more answers
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