Answer:
Explanation:
Hello,
In this case, it is convenient to compute the car's mileage in km/L as follows:
In such a way, since the distance is measured to be 250 km, the volume requirement is:
Regards.
The percentage of calcium phosphate in ore = 55. 9% so it means each 100g of ore contains 55.9 g of calcium phosphate
The formula of calcium phosphate = Ca3(PO4)3
As per molecular formula each mole of calcium phosphate contains three moles of phosphorous
mass of each mole of calcium phosphate = 310 g
for 31 g of P we need = 310 /3 g of calcium phosphate
= 103.33 g of calcium phosphate
for 1 g of P we need = 103.33 / 31 g of calcium phosphate = 3.33 g
So for 1000g of P we need = 3.33 X 1000g of calcium phosphate
= 3333.3 g of calcium phosphate
now for 55.9 g of Calcium phosphate we need = 100 g of ore
so for 3333.3 g of calcium phosphate we need = 100 X 3333.3 / 55.9 g
= 5963.03
The change in state from gas to liquid is referred as = Sublimation