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Marizza181 [45]
3 years ago
5

The weather map shown in the image forecasts the weather over a region. What causes the weather conditions shown in the map?

Chemistry
2 answers:
steposvetlana [31]3 years ago
4 0
D I believe is the answer
ser-zykov [4K]3 years ago
3 0

The correct answer is D) a cold air mass meeting a warm air mass, forming a stationary front over the region.

The weather map shown in the image forecasts the weather over a region. What causes the weather conditions shown in the map is "a cold air mass meeting a warm air mass, forming a stationary front over the region."

In Wheater terminology, a stationary front forms when to air masses collapse and none of those air masses has more power to advance over the other. It could be that warm or cold front slows down below the six miles per hour to create this stationary front. This front could cause many different weather conditions, depending on the humidity or the dryness.

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Properties of covalent compounds include: (More than 1 may be selected)
denpristay [2]

Answer:

E

C eg In graphites and diamonds

5 0
4 years ago
A certain reaction is thermodynamically favored at temperatures below 400. K, but it is not favored at temperatures above 400. K
Ilya [14]

Answer:

-0.050 kJ/mol.K

Explanation:

  • A certain reaction is thermodynamically favored at temperatures below 400. K, that is, ΔG° < 0 below 400. K
  • The reaction is not favored at temperatures above 400. K, that is. ΔG° > 0 above 400. K

All in all, ΔG° = 0 at 400. K.

We can find ΔS° using the following expression.

ΔG° = ΔH° - T.ΔS°

0 = -20 kJ/mol - 400. K .ΔS°

ΔS° = -0.050 kJ/mol.K

8 0
4 years ago
Read 2 more answers
If the volume of oxygen gas is 259 cm3 at 112 kPa, what would the volume be at 101.3 kPa?
NARA [144]

Answer:

<h3>The answer is 286.36 cm³</h3>

Explanation:

In order to find the volume be at 101.3 kPa we use Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question

P1 = 112 kPa = 112000 Pa

V1 = 259 cm³

P2 = 101.3 kPa = 101300 Pa

We have

V_2 =  \frac{112000 \times 259}{101300}  =  \frac{29008000}{101300}  \\  = 286.3573543...

We have the final answer as

<h3>286.36 cm³</h3>

Hope this helps you

6 0
3 years ago
What does it mean when water is supercooled?
Alex Ar [27]
Supercooling<span>, a state where liquids do not solidify even below their normal freezing point. Means sometimes we have liquid water below 0 degree C.</span>
4 0
3 years ago
The coordination compound Co3[Cr(CN)6]2 contains Co2+ cations and a complex anion. What is the likely oxidation state for Cr in
otez555 [7]

Answer:

-3

Explanation:

The oxidation state or oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.

The complex anion here is [Cr(CN)6]3-.

Now, as the oxidation state of CN or cyanide ligand is -1, and if we suppose the oxidation state of Cr to be 'x', then; x - 6 = -3 (overall charge on the anion),

so x= +3. Hence the oxidation state of Chromium in this complex hexacyanochromium (III) anion comes out to be -3.

.

7 0
3 years ago
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