Question

If the volume of oxygen gas is 259 cm3 at 112 kPa, what would the volume be at 101.3 kPa?

Answer 1

Answer:

The answer is 286.36 cm³

Explanation:

In order to find the volume be at 101.3 kPa we use Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

$V_2 = \frac{P_1V_1}{P_2}$

From the question

P1 = 112 kPa = 112000 Pa

V1 = 259 cm³

P2 = 101.3 kPa = 101300 Pa

We have

$V_2 = \frac{112000 \times 259}{101300} = \frac{29008000}{101300} \\ = 286.3573543...$

We have the final answer as

286.36 cm³

Hope this helps you