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kipiarov [429]
3 years ago
10

If the volume of oxygen gas is 259 cm3 at 112 kPa, what would the volume be at 101.3 kPa?

Chemistry
1 answer:
NARA [144]3 years ago
6 0

Answer:

<h3>The answer is 286.36 cm³</h3>

Explanation:

In order to find the volume be at 101.3 kPa we use Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question

P1 = 112 kPa = 112000 Pa

V1 = 259 cm³

P2 = 101.3 kPa = 101300 Pa

We have

V_2 =  \frac{112000 \times 259}{101300}  =  \frac{29008000}{101300}  \\  = 286.3573543...

We have the final answer as

<h3>286.36 cm³</h3>

Hope this helps you

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