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antoniya [11.8K]
3 years ago
7

The coordination compound Co3[Cr(CN)6]2 contains Co2+ cations and a complex anion. What is the likely oxidation state for Cr in

the anion?
Chemistry
1 answer:
otez555 [7]3 years ago
7 0

Answer:

-3

Explanation:

The oxidation state or oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.

The complex anion here is [Cr(CN)6]3-.

Now, as the oxidation state of CN or cyanide ligand is -1, and if we suppose the oxidation state of Cr to be 'x', then; x - 6 = -3 (overall charge on the anion),

so x= +3. Hence the oxidation state of Chromium in this complex hexacyanochromium (III) anion comes out to be -3.

.

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How do the particles in matter change when a substance becomes hotter, cools down, or changes state
Archy [21]
Colder- moves slower
warmer- moves faster
changes state:
    solid to gas- warmer
    gas to solid- colder
    something like that
7 0
3 years ago
To name the compound written as CuCl2, you would write:
vovangra [49]

Answer: option C. Copper (II) chloride

Explanation:

To name CuCl2, we need to know the oxidation state of Cu in the compound as chlorine always have oxidation on —1 in all its compound. The oxidation state of Cu can be calculated as follows:

Cu + 2Cl = 0 (since the compound has no charge)

Cl = —1

Cu + 2(—1) = 0

Cu —2 = 0

Collect like terms

Cu = 0 +2

Cu = +2

Therefore, the oxidation state of Cu in CuCl2 is +2.

The name of the compound will be copper(ii) chloride, since cupper has oxidation state +2 in the compound.

4 0
3 years ago
HELP PLEASE I HAVE A TEST TODAY AND I DON'T UNDERSTAND ANY OF THIS...
myrzilka [38]

Answer:

About 67 grams or 67.39 grams

Explanation:

First you would have to remember a few things:

 enthalpy to melt ice is called enthalpy of fusion.  this value is 6.02kJ/mol

  of ice  

 it takes 4.18 joules to raise 1 gram of liquid water 1 degree C

 water boils at 100 degrees C and water melts above 0 degrees C

 1 kilojoules is 1000 joules

  water's enthalpy of vaporization (steam) is 40.68 kJ/mol

  a mole of water is 18.02 grams

  we also have to assume the ice is at 0 degrees C

Step 1

Now start with your ice.  The enthalpy of fusion for ice is calculated with this formula:

q = n x ΔH    q= energy, n = moles of water, ΔH=enthalpy of fusion

Calculate how many moles of ice you have:

150g x (1 mol / 18.02 g) = 8.32 moles

Put that into the equation:

q = 8.32 mol x 6.02 = 50.09 kJ of energy to melt 150g of ice

Step 2

To raise 1 gram of water to the boiling point, it would take 4.18 joules times 100 (degrees C)  or 418 joules.

So if it takes 418 joules for just 1 gram of water, it would take 150 times that amount to raise 150g to 100 degrees C.  418 x 150 = 62,700 joules or 62.7 kilojoules.

So far you have already used 50.09 kJ to melt the ice and another 62.7 kJ to bring the water to boiling.  That's a total of 112.79 kJ.

Step 3

The final step is to see how much energy is left to vaporize the water.

Subtract the energy you used so far from what you were told you have.

265 kJ - 112.79 kJ = 152.21 kJ

Again q = mol x ΔH (vaporization)

You know you only have 152.21 kJ left so find out how many moles that will vaporize.

152.21 kJ = mol x 40.68  or   mol = 152.21 / 40.68  = 3.74 moles

This tells you that you have vaporized 3.74 moles with the energy you have left.

Convert that back to grams.

3.74 mol   x  ( 18.02 g / 1 mol ) = 67.39 grams

5 0
2 years ago
The pka value for the carboxylic acid group in acetic acid is 4.75. write the predominant structure of acetic acid at (a ph=1, (
Scorpion4ik [409]
Hello!

A) At pH=1

This pH is lower than the value for the pKa, so Acetic acid wouldn't be ionized, but the equilibrium would be displaced to CH₃COOH

CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the left)

The chemical structure for CH₃COOH is the first one in the attached images.

B) At pH=7

This pH is higher than the value for the pKa, so Acetic acid would be ionized, and the equilibrium would be displaced to CH₃COO⁻

CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the right)

The chemical structure for CH₃COO⁻ is the second one in the attached images.

Have a nice day!

7 0
3 years ago
Calcium chromate, cacro4, has a ksp of 7.1×10−4. what happens when calcium and chromate solutions are mixed to give 0.0200 m ca2
Serjik [45]

The solubility equilibrium of CaCrO_{4}:

[tex] CaCrO_{4}(aq)<===>Ca^{2+}(aq) + CrO_{4}^{2-}(aq)\\
Q_{sp}=[Ca^{2+}][CrO_{4}^{2-}]\\
= (0.0200 M)(0.0300 M) \\
= 0.0006

Ksp (0.00071) > Qsp (0.0006). So, <u>no precipitate would form</u>.

8 0
3 years ago
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