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antoniya [11.8K]
3 years ago
7

The coordination compound Co3[Cr(CN)6]2 contains Co2+ cations and a complex anion. What is the likely oxidation state for Cr in

the anion?
Chemistry
1 answer:
otez555 [7]3 years ago
7 0

Answer:

-3

Explanation:

The oxidation state or oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.

The complex anion here is [Cr(CN)6]3-.

Now, as the oxidation state of CN or cyanide ligand is -1, and if we suppose the oxidation state of Cr to be 'x', then; x - 6 = -3 (overall charge on the anion),

so x= +3. Hence the oxidation state of Chromium in this complex hexacyanochromium (III) anion comes out to be -3.

.

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The concentration of oxalate ion (C2O42-) in a sample can be determined by titration with a solution of permanganate ion (MnO4-)
zmey [24]

Answer:

0.3152 M

Explanation:

The reaction that takes place is:

  • 2MnO₄⁻ + 5C₂O₄⁻² + 16H⁺ → 2Mn⁺² + 8H₂O + 10CO₂

First we <u>calculate the MnO₄⁻ moles used up in the titration</u>, <em>by multiplying the volume times the concentration</em>:

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Then we <u>convert MnO₄⁻ moles to C₂O₄⁻² moles</u>:

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Finally we <u>calculate the oxalate ion concentration</u>,<em> by dividing the moles by the volume</em>:

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6 0
3 years ago
What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 mole of c
yuradex [85]

Answer:

Theoretical moles of V are 1.6 moles

Explanation:

The theoretical yield of a reaction is defined as the amount of product you would make if all of the limiting reactant was converted into product.

In the reaction:

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Based on the reaction, 1 mol of V2O5 needs 5 moles of Ca for a complete reaction. As there are just 4 moles, <em>limiting reactant is Ca.</em> As there are produced 2 moles of V per 5mol of Ca, Theoretical moles of V are:

4 moles of Ca × (2mol V / 5Ca) = <em>1.6 moles of V</em>

<em></em>

I hope it helps!

5 0
3 years ago
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Ne4ueva [31]
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