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Mamont248 [21]
3 years ago
12

What is the empirical formula for propene (C3H6)?

Chemistry
2 answers:
Ivenika [448]3 years ago
7 0
To determine the empirical formula or the simplest ratio of specific atoms to other atoms in a given compound, simply divide by the largest common divisible factor of the subscripts in this case it's 3.

C3H6 -> CH2.
inna [77]3 years ago
5 0

Answer: The empirical formula for propene (C_3H_6)[tex] is [tex]CH_2

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

Given : Molecular formula for propene (C_3H_6)[tex] Thus the simplest ratio of carbon and hydrogen will be 1: 2 and thus empirical formula for for propene [tex](C_3H_6)[tex] is [tex]CH_2

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Look at the dots around each symbol and the energy levels from the resources above;
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Hello! Here's the answer I was able to come up with:

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<em>What relationship do you notice between the dots in these two charts?</em>

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An atom can have a maximum of two electrons in its innermost layer. Hydrogen and helium have only one and two electrons, respectively, so they don't have enough electrons to actually have more than one layer. Therefore, their outermost layer is, in fact, their only layer. This is why the number of dots that hydrogen and helium have in their dot diagram is the same as the number of electrons shown for them on the Periodic Table.

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6 0
3 years ago
4. Synthesis problems. Propose a synthetic route from the starting material to the product. In your answer, show each individual
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5 0
1 year ago
What happens to salt water and fresh water when you try to mix them.
torisob [31]

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5 0
3 years ago
Read 2 more answers
How many moles are 4.20 * 10 ^ 25 atoms of Ca?
aleksandr82 [10.1K]

Answer:

~69.744 moles of Ca

Explanation:

Using Avogadro's constant , we know that:

1 mole = 6.022 x 10^23 atoms

S0, the number of moles in 4.20 x 10^25 atoms of Ca:

=(4.20 x 10^25 x 1 )/(6.022 x 10^23)

~69.744 moles of Ca

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S0, the number of atoms in 0.35 moles of  oxygen:

=[0.35 x (6.022 x 10^23)]

=2.1077 x 10^23 atoms of Oxygen

Hope it helps:)

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2 years ago
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