A frictionless piston-cylinder device contains a saturated liquid and water vapor mixture at 110 ℃. During a constant pressure p
1 answer:
Explanation:
(a) It is given that heat transferred is -546 kJ (as heat is releasing) and temperature is 110 degree celsius.
Hence, the temperature in kelvin will be as follows.
(110 + 273) K
= 383 K
As it is known that relation between entropy change and heat is as follows.
S =
Putting the given values in the above equation as follows.
S =
=
= -1.4255 kJ/K
As temperature changes from to
. So, (15 + 273) K = 288 K. Hence, change in entropy will be calculated as follows.
=
= 1.895 kJ/K
Therefore, entropy change of water will be 1.895 kJ/K.
(b) As total entropy generated will be the sum of both the entropies as follows.
Total entropy = (-1.4255 kJ/K + 1.895 kJ/K)
= 0.4695 kJ/K
Thus, total entropy during this heat transfer process is 0.4695 kJ/K.
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Answer:
The structures are shown in the figure.
Explanation:
The primary hydrogens are those which are attached to primary carbon.
Primary carbons are the carbons which are attached to only one carbon.
Primary carbons is bonded to three hydrogens.
In order to draw such structure we will draw structures which will have carbon with three hydrogens or no hydrogens (quaternary)
The structures are shown in the figure with clear marking.
