Explanation:
(a) It is given that heat transferred is -546 kJ (as heat is releasing) and temperature is 110 degree celsius.
Hence, the temperature in kelvin will be as follows.
(110 + 273) K
= 383 K
As it is known that relation between entropy change and heat is as follows.
S =
Putting the given values in the above equation as follows.
S =
=
= -1.4255 kJ/K
As temperature changes from to
. So, (15 + 273) K = 288 K. Hence, change in entropy will be calculated as follows.
=
= 1.895 kJ/K
Therefore, entropy change of water will be 1.895 kJ/K.
(b) As total entropy generated will be the sum of both the entropies as follows.
Total entropy = (-1.4255 kJ/K + 1.895 kJ/K)
= 0.4695 kJ/K
Thus, total entropy during this heat transfer process is 0.4695 kJ/K.
Solution :
Given :
Amount of anserine solution = 0.200 M
pH value is = 7.20
Preparation of 0.04 M solution of anserine from the 0.2 M solution.
0.2 M x = 0.04 M x 1000 ml
= 200 ml
So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.
0.1 M x = 0.04 x 1000 ml
= 400 ml
Therefore, 400 ml of HCl is needed.