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astra-53 [7]
3 years ago
15

Which is a product in the following chemical reaction? CH4 + 2O2 → CO2 + 2H2O

Chemistry
2 answers:
NeX [460]3 years ago
5 0
<span>CH4 + 2O2 → CO2 + 2H2O
</span>
The products are water (H2O) and carbon dioxide (CO2)
Kobotan [32]3 years ago
5 0

Answer : The product in the given chemical reaction are, carbon dioxide (CO_2) and water (H_2O).

Explanation :

The given balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

The give balanced chemical reaction is a balanced reaction because in this reaction all the atoms of individual elements are completely balanced.

In the chemical reaction, the species present on left side of the right arrow are the reactants and species present on right side of the right arrow are the products.

CH_4 and O_2 are the reactants.

CO_2 and H_2O are the products.

Hence, the product in the given chemical reaction are, carbon dioxide (CO_2) and water (H_2O).

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How many grams of Cl2 are in 1.20 x 1024 Cl atoms?
Vaselesa [24]
<h3>Answer:</h3>

70.906 g

<h3>Explanation:</h3>

We are given;

  • Atoms of Chlorine = 1.2 × 10^24 atoms

We are required to calculate the mass of Chlorine

  • We know that 1 mole of an element contains atoms equivalent to the Avogadro's number, 6.022 × 10^23.
  • That is , 1 mole of an element = 6.022 × 10^23 atoms
  • Therefore; 1 mole of Chlorine = 6.022 × 10^23 atoms

But since Chlorine gas is a molecule;

  • 1 mole of Chlorine gas = 2 × 6.022 × 10^23 atoms

But, molar mass of Chlorine gas = 70.906 g/mol

Then;

70.906 g Of chlorine gas = 2 × 6.022 × 10^23 atoms

                                          = 1.20 × 10^24 atoms

Thus;

For 1.2 × 10^24 atoms ;

= ( 70.906 g/mol × 1.2 × 10^24 atoms ) ÷ (1.20 × 10^24 atoms)

<h3>=  70.906 g </h3>

Therefore, 1.20 × 10^24 atoms of chlorine contains a mass of 70.906 g

=  

5 0
3 years ago
What is the density of a rectangle solid with dimensions
Hunter-Best [27]

Answer:

5625000gm/cm^3

Explanation:

volume=w*h*l=25*15*5=1875cm^3

density=mass*volume

=1875*3000

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8 0
3 years ago
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