Which is a product in the following chemical reaction? CH4 + 2O2 → CO2 + 2H2O

Chemistry

2 answers:

NeX [460]3 years ago

5 0

<span>CH4 + 2O2 → CO2 + 2H2O
</span>
The products are water (H2O) and carbon dioxide (CO2)

Kobotan [32]3 years ago

5 0

Answer : The product in the given chemical reaction are, carbon dioxide $(CO_2)$ and water $(H_2O)$ .

Explanation :

The given balanced chemical reaction is,

$CH_4+2O_2\rightarrow CO_2+2H_2O$

The give balanced chemical reaction is a balanced reaction because in this reaction all the atoms of individual elements are completely balanced.

In the chemical reaction, the species present on left side of the right arrow are the reactants and species present on right side of the right arrow are the products.

$CH_4$ and $O_2$ are the reactants.

$CO_2$ and $H_2O$ are the products.

Hence, the product in the given chemical reaction are, carbon dioxide $(CO_2)$ and water $(H_2O)$ .

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Find the equilibrium value of [CO] if Kc=14.5 : CO (g) + 2H2 (g) ↔ CH3OH (g) Equilibrium concentrations: [H2] = 0.322 M and [CH3

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Answer:

The equilibrium value of [CO] is 1.04 M

Explanation:

Chemical equilibrium is the state to which a spontaneously evolving chemical system, in which a reversible chemical reaction takes place. When this situation is reached, it is observed that the concentrations of substances, both reagents and reaction products, they remain constant over time. That is, the rate of reaction of reagents to products is the same as that of products to reagents.

Reagent concentrations and products in equilibrium are related by the equilibrium constant Kc. Being:

aA + bB ⇔ cC + dD

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }$

Then this constant Kces equals the multiplication of the concentrations of the products raised to their stoichiometric coefficients between the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

In this case:

$Kc=\frac{[CH_{3}OH ]}{[CO]*[H_{2} ]^{2} }$