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3 years ago

ANSWER ASAP . Which of the screws below requires the least amount of effort force to turn?

Physics

2 answers:

emmasim [6.3K]3 years ago

6 0

Answer:

The answer is screw x

Explanation:

A screw is an inclined plane that spirals around a cylinder. To help visualize this, imagine a playground slide that sprirals around a central pole. The threads on a screw are the outside edge of a plane that wraps around the screw's central axis.

The closer together a screw's threads are, the longer the inclined plane. The longer the inclined plane, the less effort force required to turn the screw. The screw in image X requires the least amount of effort force to turn because its threads are the closest together.

tigry1 [53]3 years ago

4 0

Answer:

Screw X

Explanation:

In the screw x, the threads of the inclined plane are closer together. Therefore this screw has a greater mechanical advantage and hence it is easier to turn than the other screws.
Therefore,it takes less force to penetrate the wood with the screw X.

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Two car collide in an intersection. The speed limit in that zone is 30 mph. The car (mass of 1250 kg) was going 17.4 m/s (38.9).

Musya8 [376]

Answer:

u₂ = 3.7 m/s

Explanation:

Here, we use the law of conservation of momentum, as follows:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\$

where,

m₁ = mass of the car = 1250 kg

m₂ = mass of the truck = 2020 kg

u₁ = initial speed of the car before collision = 17.4 m/s

u₂ = initial speed of the tuck before collision = ?

v₁ = final speed of the car after collision = 6.7 m/s

v₂ = final speed of the truck after collision = 10.3 m/s

Therefore,

$(1250\ kg)(17.4\ m/s)+(2020\ kg)(u_2)=(1250\ kg)(6.7\ m/s)+(2020\ kg)(10.3\ m/s)\\\\(2020\ kg)(u_2) = 8375\ N.s + 20806\ N.s - 21750\ N.s\\\\u_2=\frac{7431\ N.s}{2020\ kg}$

u₂ = 3.7 m/s

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