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nikklg [1K]
3 years ago
10

Write the net ionic equation for the following molecular equation Mg (s) +Snso (aq) Mgso4 (aq) Sn(s) Use the lowest possible coe

fficients. Use the pull-down boxes to specify states such as (aa) or (s). If a box is not needed, leave it blank.)
Chemistry
1 answer:
Simora [160]3 years ago
3 0

Answer:

Mg(s) + Sn²⁺(aq) ⇄ Mg²⁺(aq) + Sn(s)

Explanation:

Let's consider the following molecular equation.

Mg(s) + SnSO₄(aq) ⇄ MgSO₄(aq) + Sn(s)

The full ionic equation includes al the ions and the species that do not dissociate in water.

Mg(s) + Sn²⁺(aq) + SO₄²⁻(aq) ⇄ Mg²⁺(aq) + SO₄²⁻(aq) + Sn(s)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the species that do not dissociate in water.

Mg(s) + Sn²⁺(aq) ⇄ Mg²⁺(aq) + Sn(s)

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The reactions listed below are either chemical reactions or nuclear reactions. which are nuclear reactions? check all that apply
prohojiy [21]

The equations that are nuclear reactions are as follows:

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<h3>What is nuclear reaction?</h3>

A nuclear reaction is a reaction that involves the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and/or subatomic particles in which the number of protons and/or neutrons in a nucleus changes.

The products of a nuclear reaction may contain a different element or a different isotope of the same element.

Therefore, the equations that are nuclear reactions are as follows:

  • superscript 185 subscript 79 upper Au right arrow superscript 181 subscript 77
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8 0
2 years ago
Be sure to answer all parts. A freshly isolated sample of 90Y was found to have an activity of 2.2 × 105 disintegrations per min
Leokris [45]

Answer:

The half-life is  t_h = 3.856*10^{3} minute

Explanation:

From the question we are told that

     The sample is  90 Y

      The first  activity is  A_1  = 2.2 *10^5  per minute

       The second  activity is  A_2  = 5.8 *10^3  per minute

        The duration from 1:00 p.m. on December 3, 2006 to 2:15 p.m. on December 17, 2006   is

               t = 14 \ days \ 1 hr \ 15 min

Converting to minutes we have  

               t =  (14 * 24 * 60) +  (1* 60) + 15

               t = 20235 \ minutes

The first order rate constant for this disintegrations can be mathematically represented  as

               ln \frac{A_2}{A_1}  =  - \lambda t

 Where \lambda is the rate constant

    Substituting values

                     ln [\frac{5.8 * 10^{3}}{2.2 *10^{5}} ] = -  \lambda * 20235

                    -3.6358 = -  \lambda * 20235

So

                \lambda =  \frac{3.6358}{20235}

                    \lambda = 1.7968 *10^{-4} minute^{-1}

The half life is mathematically represented as

               t_{h} = \frac{0.693}{\lambda }

So           t_h = \frac{0.693}{1.7968 *10^{-4}}

              t_h = 3.856*10^{3} minute

               

5 0
3 years ago
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