Given that the rope is not moving (acceleration is zero), by the second Law of Newton (F=m*a), the net force acting on the rope is zero.
Then, the force applied by the team B equals the force applied by the tema A: 103 N.
So I'm a junior. I am currently taking AP Calc BC and AP Physics B.
As of now, I'm not sure if I should take AP Probability and Statistics or Differential Equations/Calc III next year. Also, I'm debating between taking AP Physics C or AP Chemistry.
Which ones do you think would look better on a transcript? I heard that Diffeq/CalcIII is harder than AP ProbStat, but ProbStat is an AP course which will be weighted heavier. Also, should I take Physics C since i've taken Physics B this year already?
Answer:
Explanation:
Given,
Width of rectangular tank, b = 1 m
Length of the tank, l = 2 m
height of the tank, d = 1.5 m
Depth of gasoline on the tank, h = 1 m
The differential form with the acceleration
acceleration in z-direction = 0 m/s²
g = 9.8 m/s²
a_y is the horizontal acceleration of the gasoline.
Hence, Horizontal acceleration of the gasoline before gasoline would spill is equal to 4.9 m/s²
The approximate lateral area of the prism is determined as 831 square inches.
<h3>
What is lateral area of the hexagonal prism?</h3>
The lateral area of the hexagonal prism is calculated as follows;
LA = PH
where;
- P is perimeter of the prism
- H is height
A = ¹/₂Pa
where;
- a is apothem = 10 inches
- A is base area = 346.41 in²
346.41 = ¹/₂(10)P
346.41 = 5P
P = 346.41/5
P = 69.282 inches
LA = PH
LA = 69.282 x 12
LA = 831.38 in²
Learn more about lateral area of prism here: brainly.com/question/296674
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