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exis [7]
3 years ago
7

HELPHELPHELPHELPHELPPLZZZZZ What is the name for the type of graph shown in the image below? A graph that shows quantities of it

ems arranged in particular classes or groups a. Bar graph b. Cumulative frequency c. Histogram d.Stem-and-leaf
Physics
1 answer:
kow [346]3 years ago
3 0

Answer:a graph

Explanation:because it graphs

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How long will it take a basketball starting from rest to roll without slipping 2.6 m down an incline that makes an angle of 30.8
Romashka-Z-Leto [24]

Answer:

<em>t = 1.02 s</em>

Explanation:

friction = 0 N (no slipping)

downward force along the inclined plane = F = mgsin(30.8)

                                                                        F = ma

⇒                                                                      a = 9.81 sin(30.8)

                                                                         a = 5.02 m/s^2

now we have

displacement = s = 2.6 m

acceleration   = a = 5.02m/s^2

initial velocity = Vi = 0m/s

time                 = t =  ?

<u>APPLYING THE 2ND EQUATION OF MOTION:</u>

<em>    S = (Vi)(t)+0.5at^2</em>

<em>2.6 = 0(t) + 0.5 * 5.02 * t^2</em>

<em>t = 1.02 s</em>

7 0
3 years ago
Photoelectric effect definition
xenn [34]
Photoelectric effect is the emission of electrons by a substance that has been subjected to electromagnetic energy 
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4 years ago
The energy of a wave is directly proportional to the square of the ___. D.Amplitude c. crest b. wavelength a.frequency
IRISSAK [1]

The energy of a wave is directly proportional to the square of the D.Amplitude

the energy of a wave is given as

E = (0.5) (μ v t ) w² A²

where t = time

μ = mass per unit length of the string

v = wave propagation of velocity.

w = angular frequency

A = amplitude

E = energy of wave

From the equation , we see that

the energy of wave "E" is directly proportional to A².

hence the correct choice is D. Amplitude.

4 0
3 years ago
A 60 g ball is dropped from rest from a height of 2.4 m. It bounces off the floor and rebounds to a maximum height of 1.9 m. If
kap26 [50]

Answer:

The force is 1.34 newtons and its direction is upward.

Explanation:

Choosing positive direction pointing towards the floor in this collision we're going to use the momentum-impulse theorem that states:

J=\Delta p (1)

with \Delta p=p_f-p_i the change in the momentum and J the impulse, with pi the initial momentum that is the momentum just before the collision and pf the final momentum th is the momentum just after the collision. The impulse J is also defined as:

J=F_{avg}\Delta t(2)

with F_{avg} the average force and \Delta t the time the collision lasts

We can equate expressions (2) and (1):

\Delta p=p_f-p_i=F_{avg}\Delta t

Using the definition of linear momentum as mass (m) time velocity (v):

mv_f-mv_i=F_{avg}\Delta t

We can solve for Favg:

F_{avg}=\frac{m(v_f-v_i)}{\Delta t} (3)

Now we should find the velocities vf and vi, we should do this using conservation of energy:

For the velocity the ball has just before reaches the floor:

U_i=K_f

With Ui the initial potential energy (there is not initial kinetic energy) and Kf the final kinetic energy (there is not final potential energy), then:

mgh=\frac{mv_i^2}{2}

solving for vi:

v_i=\sqrt{2gh}=\sqrt{2*9.81*2.4}=6.86\frac{m}{s}

For the velocity the ball has just after bounces the floor:

K_i=U_f

There is not initial potential energy because it's a floor level at this instant, and the there is not final kinetic energy because the ball has instantly zero velocity at its maximum height (hm), then:

\frac{mf_i^2}{2}=mgh_m

solvig for vf:

v_f=\sqrt{2gh_m}=\sqrt{2*9.81*1.9}=6.10\frac{m}{s}

Using vf and vi on (3):

F_{avg}=\frac{(0.06)(6.10-6.86)}{0.034}=-1.34 N

The negative sign indicates the direction of the force is pointing away the floor

4 0
3 years ago
Two waves travel through ocean, one with wavelength 3 m, one with 6 m. Which one has greater speed?
spin [16.1K]

Answer: 6m

Explanation: 6 is more than 3 and their both being measured by m

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