Answer:
electrical conductivity in liquid solutions depends on the availability of free ions.
Answer:879.29 N-m
Explanation:
Given
mass of first child ![m_1=44 kg](https://tex.z-dn.net/?f=m_1%3D44%20kg)
distance of first child from tree is ![r_1=1 m](https://tex.z-dn.net/?f=r_1%3D1%20m)
tree is inclined at an angle of ![\theta =27^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%20%3D27%5E%7B%5Ccirc%7D)
mass of second child ![m_1=27 kg](https://tex.z-dn.net/?f=m_1%3D27%20kg)
distance of second child from tree is ![r_2=2.1 m](https://tex.z-dn.net/?f=r_2%3D2.1%20m)
Weight of first child![=m_1g=431.2 kg](https://tex.z-dn.net/?f=%3Dm_1g%3D431.2%20kg)
Weight of second child![=m_2g=264.6 kg](https://tex.z-dn.net/?f=%3Dm_2g%3D264.6%20kg)
Torque of first child weight![=m_1g\cos \theta \cdot r_1](https://tex.z-dn.net/?f=%3Dm_1g%5Ccos%20%5Ctheta%20%5Ccdot%20r_1)
![T_1=44\times 9.8\times \cos 27\times 1=384.202 N-m](https://tex.z-dn.net/?f=T_1%3D44%5Ctimes%209.8%5Ctimes%20%5Ccos%2027%5Ctimes%201%3D384.202%20N-m)
Torque of second child weight![=m_2g\cos \theta \cdot r_2](https://tex.z-dn.net/?f=%3Dm_2g%5Ccos%20%5Ctheta%20%5Ccdot%20r_2)
![T_2=27\times 9.8\times \cos 27\times 2.1=495.096 N-m](https://tex.z-dn.net/?f=T_2%3D27%5Ctimes%209.8%5Ctimes%20%5Ccos%2027%5Ctimes%202.1%3D495.096%20N-m)
Net torque ![T_{net}=T_1+T_2=384.202+495.096=879.29 N-m](https://tex.z-dn.net/?f=T_%7Bnet%7D%3DT_1%2BT_2%3D384.202%2B495.096%3D879.29%20N-m)
Kinetic energy =
1/2 (mass) • (velocity squared).
I don't see distance in that formula anywhere, so they're not related.
Sea scorpions or Eurypterids lived about 251.9 million years ago. They were formidable predators and hunters, but they were wiped out in the Great Permian Mass Extinction, which is also known as the Great Dying (96% of all species on Earth went extinct).The largest species like Jaekelopterus was over 7 feet long! They were mainly thought to go extinct because of a slew of natural disasters that occurred when a comet hit the Earth, as well as increased volcanic activity polluting the seas that Sea scorpions lived in, as well as rising sea temperatures. The Silurian, when these Sea scorpions proliferated was when the water was cooler, holding in more nutrients, allowing both Sea Scorpions and other animals to spread all over the world. But as the oceans became polluted from the volcanoes (and the ash they produced) and the global ocean temperatures began to rise, many animals may not have been able to cope or adapt to the extreme change, becoming helpless in their nutrient deficient water (compared to what they were used to).
I hope this helps!
Answer:
![|a|=2.83\ m/s^2](https://tex.z-dn.net/?f=%7Ca%7C%3D2.83%5C%20m%2Fs%5E2)
![\theta=75^o](https://tex.z-dn.net/?f=%5Ctheta%3D75%5Eo)
Explanation:
<u>Net Force And Acceleration
</u>
The Newton's second law relates the net force applied on an object of mass m and the acceleration it aquires by
![\vec F_n=m\vec a](https://tex.z-dn.net/?f=%5Cvec%20F_n%3Dm%5Cvec%20a)
The net force is the vector sum of all forces. In this problem, we are not given the magnitude of each force, only their angles. For the sake of solving the problem and giving a good guide on how to proceed with similar problems, we'll assume both forces have equal magnitudes of F=40 N
The components of the first force are
![\vec F_1=](https://tex.z-dn.net/?f=%5Cvec%20F_1%3D%3C40cos30%5Eo%2C40sin30%5Eo%3E)
![\vec F_1=\ N](https://tex.z-dn.net/?f=%5Cvec%20F_1%3D%3C20%5Csqrt%7B3%7D%2C20%3E%5C%20N)
The components of the second force are
![\vec F_2=](https://tex.z-dn.net/?f=%5Cvec%20F_2%3D%3C40cos120%5Eo%2C40sin120%5Eo%3E)
![\vec F_2=\ N](https://tex.z-dn.net/?f=%5Cvec%20F_2%3D%3C-20%2C20%5Csqrt%7B3%7D%3E%5C%20N)
The net force is
![\vec F_n=](https://tex.z-dn.net/?f=%5Cvec%20F_n%3D%3C20%5Csqrt%7B3%7D-20%2C20%2B20%5Csqrt%7B3%7D%3E)
![\vec F_n=\ N](https://tex.z-dn.net/?f=%5Cvec%20F_n%3D%3C14.64%2C54.64%3E%5C%20N)
The magnitude of the net force is
![|F_n|=\sqrt{14.64^2+54.64^2}](https://tex.z-dn.net/?f=%7CF_n%7C%3D%5Csqrt%7B14.64%5E2%2B54.64%5E2%7D)
![|F_n|=\sqrt{3200}=56.57\ N](https://tex.z-dn.net/?f=%7CF_n%7C%3D%5Csqrt%7B3200%7D%3D56.57%5C%20N)
The acceleration has a magnitude of
![\displaystyle |a|=\frac{|F_n|}{m}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%7Ca%7C%3D%5Cfrac%7B%7CF_n%7C%7D%7Bm%7D)
![\displaystyle |a|=\frac{56.57}{20}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%7Ca%7C%3D%5Cfrac%7B56.57%7D%7B20%7D)
![|a|=2.83\ m/s^2](https://tex.z-dn.net/?f=%7Ca%7C%3D2.83%5C%20m%2Fs%5E2)
The direction of the acceleration is the same as the net force:
![\displaystyle tan\theta=\frac{54.64}{14.64}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20tan%5Ctheta%3D%5Cfrac%7B54.64%7D%7B14.64%7D)
![\theta=75^o](https://tex.z-dn.net/?f=%5Ctheta%3D75%5Eo)