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Cloud [144]
4 years ago
10

So how would you break down the problem(2x-5)^2=49

Mathematics
2 answers:
BigorU [14]4 years ago
4 0
First, simplify the equation.

4x2−20x+25=<span>49
</span>
Step 2: Subtract 49 from both sides.

<span><span>4x2−20x+25</span>=<span>49 - 49

</span></span><span><span>4x2−20x</span>−24 </span>=<span>0
</span>
Step 3: Factor left side of equation.

<span><span><span>4<span>(x+1)</span></span><span>(x−6)</span></span>=<span>0

</span></span>Step 4: Set factors equal to 0.

<span><span><span>x+1</span>=<span><span><span>0<span> or </span></span>x</span>−6</span></span>=0

Your answers:
</span><span><span>x=<span>−<span><span>1<span> or </span></span>x</span></span></span>=6</span><span>
</span><span>

</span>
ivanzaharov [21]4 years ago
3 0
To solve this you first expand the brackets.
4x^2 - 20x + 25 = 49
Then make it equal 0.
4x^2 - 20x - 24 = 0
Now solve the quardratic.

x^2 - 5x - 6 = 0
(x - 6)(x + 1) = 0
x = 6 or x = -1
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Step-by-step explanation:Hope this Helps you!

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Ben has b dollars. Cam has 7 fewer dollars than Ben. How many dollars does Cam have? Write your answer as an expression.
Citrus2011 [14]
B - 7 
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7 0
3 years ago
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You have a stack of 99 different books, and you are putting them all on your shelf. How many different ways are there for you to
Tanzania [10]

Answer:

9.332622\times 10^{155}

Step-by-step explanation:

Before getting the final result, let's analyse the same situation but with less books for having a better perspective. For example, just 3 books, named: A, B and C

3 books mean 3 spaces

At the beginning, the first space has 3 ways to be occupied: they are book A, B or C.

If the first place is already occupied for any of them, then, the second place could be occupied just by the two others. If the second place is occupied by any of those two, finally, the third space just could be occupied by one.

Imagine that first space is occupied by book A. The ways to arrange the other books would be:

  1. Book A ----- Book B ----- Book C
  2. Book A ----- Book C ----- Book D

As you see, there are two ways to arrange them positioning the book A at the beginning. The same would happen with book B and book C at the beginning. It means there are 3 options at the beginning and then just 2.

If we multiply those values we get the total ways. It means 6 ways.

Real Problem

Now, for the 99 different books the analysis would be the same:

At the beginning would be 99 books to put in the first space, then in the second space would be 98, then 97, then 96, and so on, until 1.

But it is not a problem because there is a way to write it. It is called factorial.

99! = 99\times 98\times 97\times 96\times ...\times 3\times 2\times 1

If we make all this multiplication we get 9.332622\times 10^{155} ways to order the 99 books.

8 0
4 years ago
Check all that apply please
luda_lava [24]

Answer: A & B

<u>Step-by-step explanation:</u>

\sqrt{5} *\sqrt{5} = \sqrt{5*5} = \sqrt{25} = 5

7 0
4 years ago
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