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Cloud [144]
3 years ago
10

So how would you break down the problem(2x-5)^2=49

Mathematics
2 answers:
BigorU [14]3 years ago
4 0
First, simplify the equation.

4x2−20x+25=<span>49
</span>
Step 2: Subtract 49 from both sides.

<span><span>4x2−20x+25</span>=<span>49 - 49

</span></span><span><span>4x2−20x</span>−24 </span>=<span>0
</span>
Step 3: Factor left side of equation.

<span><span><span>4<span>(x+1)</span></span><span>(x−6)</span></span>=<span>0

</span></span>Step 4: Set factors equal to 0.

<span><span><span>x+1</span>=<span><span><span>0<span> or </span></span>x</span>−6</span></span>=0

Your answers:
</span><span><span>x=<span>−<span><span>1<span> or </span></span>x</span></span></span>=6</span><span>
</span><span>

</span>
ivanzaharov [21]3 years ago
3 0
To solve this you first expand the brackets.
4x^2 - 20x + 25 = 49
Then make it equal 0.
4x^2 - 20x - 24 = 0
Now solve the quardratic.

x^2 - 5x - 6 = 0
(x - 6)(x + 1) = 0
x = 6 or x = -1
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