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3 years ago

So how would you break down the problem(2x-5)^2=49

2 answers:

4 0

First, simplify the equation.

4x2−20x+25=49

Step 2: Subtract 49 from both sides.

4x2−20x+25=49 - 49

4x2−20x−24 =0

Step 3: Factor left side of equation.

4(x+1)(x−6)=0

Step 4: Set factors equal to 0.

x+1=0 or x−6=0

Your answers:
x=−1 or x=6

ivanzaharov [21]3 years ago

3 0

To solve this you first expand the brackets.
4x^2 - 20x + 25 = 49
Then make it equal 0.
4x^2 - 20x - 24 = 0
Now solve the quardratic.

x^2 - 5x - 6 = 0
(x - 6)(x + 1) = 0
x = 6 or x = -1

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