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Free_Kalibri [48]
3 years ago
15

How much heat is released when a 10.0-g sample of iron cools from 75.0°c to 25.5 °c? the specific heat capacity of iron is 0.449

j/g · °c?
Physics
1 answer:
GalinKa [24]3 years ago
8 0
M = 10.0 g, the mass of the iron sample
ΔT = 75 - 25.2 = 49.5°C, the decrease in temperature
c = 0.449 J/(g-°C), the specific heat of iron

The heat released is
Q = m*c*ΔT
    = (10.0 g)*(0.449 J/(g-°C))*(49.5 C)
    = 222.255 J

Answer: 222.3 J (nearest tenth)

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Read 2 more answers
Two +1 C charges are separated by 30000 m, what is the magnitude of<br> the force?
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<em>The magnitude of the force is 10 N</em>

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<u>Coulomb's Law</u>

The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

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k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

We have two identical charges of q1=q2=1 c separated by d=30000 m, thus the magnitude of the force is:

\displaystyle F=9\cdot 10^9\frac{1*1}{30000^2}

\displaystyle F=9\cdot 10^9\frac{1*1}{30000^2}

F = 10 N

The magnitude of the force is 10 N

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3 years ago
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