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Solnce55 [7]
3 years ago
8

What is the total charge of an ionic compound

Chemistry
1 answer:
SIZIF [17.4K]3 years ago
4 0

Answer:

Zero

Explanation:a ionic compound consists of an equal number or positive and negative ions

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How many grams of KCO3 are needed to make 20 L of a 2.5 M solution?
PolarNik [594]

Answer:

0.25 L of a solution with a molarity of 6M has 6*0.25 = 1.5 moles of the solute. The molar mass of ammonium sulfate is 132.14 g/mole. The mass of 1.5 moles is 132.14*1.5 = 198.21 g. Therefore 198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.

Explanation:

7 0
4 years ago
A protein denatures when you cook it at 60°C. What is that temperature on the
seropon [69]

Answer:

333K

Explanation:

Answer is actually 333.15, but to round it off, is 333

7 0
3 years ago
Which is the smallest?<br> A) 1.3 x 1020<br> B) 2.9 x 1021<br> C) 9.5 x 1032<br> d) 8.4 x 1019
alexgriva [62]
Answer: A, 1.3*1020, 1326

A. 1326

B. 2960.9

C. 9804

D. 8559.6
7 0
4 years ago
Read 2 more answers
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of a
balandron [24]

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

6 0
3 years ago
It all adds up worksheet
Komok [63]
Atomic number and the number of protons are the same...
Neutrons = Mass number - number of protons
Electrons are same # unless there is a charge 
The whole number you see on the periodic table is the atomic number of the element which is also same as the number of protons

1) carbon - 14  ;  Mass number = 14 , Protons = 6 , Neutrons = 14 - 6 = 8 
                                Electrons = 6 

2) Lead - 208  ; Mass # = 208 , Protons = 82 , Neutrons = 208 - 82 = 126
                          Electrons = 82

3) Uranium - 239 ; Mass # = 239  , Protons  =  92,Neutrons = 239 - 92 = 147
                                 Electrons =  92

4) Uranium - 238  ; Mass # = 238 , Protons = 92 , Neutrons = 238 - 92 = 146
                                   
Electrons = 92 

5) Tin - 118  ; Mass # = 118 , Protons = 50 , Neutrons = 118 - 50 = 68
                         Electrons = 50
8 0
3 years ago
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