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Andrews [41]
4 years ago
6

When a diprotic acid, , is titrated with , the protons on the diprotic acid are generally removed one at a time, resulting in a

pH curve that has the following generic shape: Notice that the plot has essentially two titration curves. If the first equivalence point occurs at 100.0 mL added, what volume of added corresponds to the second equivalence point? Volume = mL For the following volumes of added, list the major species present after the reacts completely.
Chemistry
1 answer:
marshall27 [118]4 years ago
4 0

Answer:

At the second equivalent point 200 mL of NaOH is required.

Explanation:

at the first equivalent point:

                              H2A    +     OH-       =     HA-  +     H2O

initial mmoles        y*100         y*100            -                -

final mmoles            0                0                 y*100       y*100

at the second equivalent point:

                              HA-    +     OH-       =     A2-  +     H2O

initial mmoles        y*100         y*100            -                -

final mmoles            -                -                 y*100       y*100

at the second equivalent point we have that y*100 mmoles of NaOH or 100 mL of NaOH ir required, thus:

at the second equivalent point 200 mL of NaOH is required.

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Answer:

0.15008\ \text{g}

3.23\times 10^{21}

Explanation:

1 mol of nitrogen at STP = 22.4 L = 22400 cc

n = Mol of N_2 = \dfrac{120}{22400}=0.00536\ \text{mol}

M = Molar mass of N_2 = 28\ \text{g/mol}

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Mass of N_2 is

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Number of molecules is given by

nN_A=0.00536\times 6.022\times 10^{23}=3.23\times 10^{21}\ \text{molecules}

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