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Roman55 [17]
3 years ago
8

Planet P has a rocky surface and a radius of 9250 km. At height h above the surface, the gravitational acceleration is What is h

? 2100 km 4960 km 3890 km 2810 km
Chemistry
1 answer:
cricket20 [7]3 years ago
5 0
G all please come to mpu-xcny-did
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7 0
3 years ago
Determine the potential deaths resulting from the following exposure to chlorine:
jekas [21]

Answer:

For each scenario as following:

A. 3 Potential deaths by chlorine exposure

B. 1 Potential deaths by chlorine exposure

C. 3 Potential deaths by chlorine exposure

Explanation:

According to Freitag, 1941 Chlorine exposure can be lethal at the concentration of 34-51 ppm in a time of 1h-1.5h. The answers are based on his reference.

6 0
3 years ago
The balanced chemical equation for the reaction of copper (Cu) and silver nitrate (AgNO3) is shown below.
lesantik [10]
Remark
The balance numbers in front of Ag and AgNO3 are both 2. That number is in moles.

Rule: if the moles are the same in the equation, then whatever you are given for one, will be the same for the other. So you have 0.854 moles of Ag. You will also have 0.854 moles of AgNO3 

Answer: 0.854 <<<<<
8 0
2 years ago
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ollegr [7]

Answer:

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Explanation:

3 0
2 years ago
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A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr
sergey [27]

Answer:

184.62 ml

Explanation:

Let p_1, v_1, and T_1 be the initial and p_2, v_2, and T_2 be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

p_1=p_2 ...(i)

v_1 = 200 ml

T_1= 26 ^{\circ}C = 273+26 =299 K

T_2= 3 ^{\circ}C = 273+3 =276 K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)

For the final condition,

p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)

Equating equation (i), and (ii)

\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}

\frac{v_1}{T_1}=\frac{v_2}{T_2}  [from equation (i)]

v_2=\frac{T_2}{T_1} \times v_1

Putting all the given values, we have

v_2=\frac{276}{299} \times 200 = 184.62 \; ml

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

7 0
2 years ago
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