STP (Standard Temperature and Pressure) has the following conditions:
Temperature = 273.15 K = 0°C
Pressure = 101325 Pa = 101.325 KPa = 1 atm
We also know that 1 mole = 6.022x10^23 molecules
Using the ideal gas equation: PV=nRT
n/V = P/RT
molecules/V = P*6.022x10^23/RT
molecules/V = 101325 Pa (6.022x10^23 molecules/mole)/ (8.314 Pa-m3/mol-K)(273.15K)
molecules/V = 7.339x10^27 molecules/m^3 - Final answer
Answer:
A. A potential energy function can be specified for a conservative force.
TRUE
because there is no loss of energy in conservative type of forces.
B. A nonconservative force permits a two-way conversion between kinetic and potential energies.
FALSE
It is not true because energy is not conserved in non-conservative forces.
C. The work done by a nonconservative force depends on the path taken.
TRUE
It depends on total path length while in conservative it only depends on initial and final state
D. A potential energy function can be specified for a nonconservative force.
FALSE
Since energy is not stored in non-conservative forces so it is not defined for non conservative forces
E. A conservative force permits a two-way conversion between kinetic and potential energies.
TRUE
Work done against conservative forces is stored in form of potential energy so it is possible to have two way conversion.
F. The work done by a conservative force depends on the path taken.
FALSE
Conservative force work depends only on initial and final state
Answer:12.8°c
Explanation:
specific heat capacity of copper(c)=0.39J*g°c
Mass(m)=20grams
Quantity of heat(Q)=100joules
Temperature rise(@)=?
@=Q/(mxc)
@=100/(20x0.39)
@=100/7.8
@=12.8°c
This condition is called Galileo's Law of Inertia which states that all bodies accelerate at the smart rate , no matter what are their masses or size. Inertia is that tendency of matter to resist changes in its velocity. <span>Isaac Newton's first law of motion captures the concept of inertia. </span>
Answer:
Option D
Explanation:
The work done can be given by the mechanical energy used to do work, i.e., Kinetic energy and potential energy provided to do the work.
In all the cases, except option D, the energy provided to do the useful work is not zero and hence work done is not zero.
In option D, the box is being pulled with constant velocity, making the acceleration zero and thus Kinetic energy of the system is zero. Hence work done in this case is zero.