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vovikov84 [41]
3 years ago
14

Choose all the correct information concerning chemical reactions: Involves small amounts of energy. Some of the mass is converte

d into energy. Involves large amounts of energy. Only electrons are involved. The mass remains the same. Involves the nuclei of the atoms.
Chemistry
2 answers:
suter [353]3 years ago
8 0
<span>A chemical reactions :
Involves small amounts of energy.
</span><span> Only electrons are involved.
</span><span>The mass remains the same.</span>
viva [34]3 years ago
8 0
The correct answers are:
<span>Involves small amounts of energy.
</span><span>Only electrons are involved.
</span><span>The mass remains the same.</span>

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Suppose that a sample of gas occupies 187 mL
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Answer:

V2 = 90.7 mL

Explanation:

pressure and volume are inversely proportional, if the pressure is increased, the volume will decrease. In an isothermal process:

p1V1 = p2V2

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V2 = 90.7 mL

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If you know the number of protons, how do you find the number of electrons
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to find the number of electrons you need the charge of the element.

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How Non-Polar Molecule disolves in Non-Polar Molecule?
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Explanation:

Nonpolar compounds do not dissolve in water. The attractive forces that operate between the particles in a nonpolar compound are weak dispersion forces. However, the nonpolar molecules are more attracted to themselves than they are to the polar water molecules.

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3 years ago
How many grams of neutral salt will be obtained in the reaction of calcium oxide with 200 cm 3 of phosphoric acid solution whose
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Answer:

9.3 g of Ca3(PO4)2

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3CaO + 2H3PO4 —> Ca3(PO4)2 + 3H2O

Next, we shall determine the number of mole of H3PO4 present in 200 cm³ of 0.3 mol/dm³ phosphoric acid (H3PO4) solution. This can be obtained as follow:

Molarity of H3PO4 = 0.3 mol/dm³

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Mole of H3PO4 =?

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Cross multiply

Mole of H3PO4 = 0.3 × 0.2

Mole of H3PO4 = 0.06 mole

Next, we shall determine the number of mole of the salt, Ca3(PO4)2, obtained from the reaction. This can be obtained as shown below:

3CaO + 2H3PO4 —> Ca3(PO4)2 + 3H2O

From the balanced equation above,

2 moles of H3PO4 reacted to produced 1 mole of Ca3(PO4)2.

Therefore, 0.06 moles of H3PO4 will react to produce = (0.06 × 1)/2 = 0.03 mole of Ca3(PO4)2.

Thus, 0.03 mole of Ca3(PO4)2 is produced from the reaction.

Finally, we shall determine the mass of Ca3(PO4)2 produced as follow:

Mole of Ca3(PO4)2 = 0.03 mole

Molar mass of Ca3(PO4)2 = (40×3) + 2[31 + (16×4)]

= 120 + 2[31 + 64]

= 120 + 2[95]

= 120 + 190

= 310 g/mol

Mass of Ca3(PO4)2 =?

Mole = mass /Molar mass

0.03 = mass of Ca3(PO4)2 / 310

Cross multiply

Mass of Ca3(PO4)2 = 0.03 × 310

Mass of Ca3(PO4)2 = 9.3 g

Thus, 9.3 g of Ca3(PO4)2 was obtained from the reaction.

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When we don't use prefixe ina binary compound​
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Answer:

Explanation:

Answer will be wrong

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