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3 years ago

I am doing an experiment that calls for 200g of H2SO4. How many moles of H2SO4 is this?

Chemistry

1 answer:

Mila [183]3 years ago

4 0

Answer: 2.04 moles

Explanation:

Mass of H2SO4 = 200g

RMM of H2SO4 = (2*1) + 32 + (16*4)

= 2 +32 +64 = 98

n = Mass concentration / RMM

n = 200/98

n = 2.04moles

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Weak acids are poor conductors of:

valentina_108 [34]

Answer: Weak acids are poor conductors of electricity.

Explanation:

Weak acids are defined as the acids which dissociate weakly or partially when dissolved in water (polar solvent).

For example, $CH_3COOH \rightleftharpoons CH_3COO^{-} + H^{+}$

Due to less dissociation there will be less number of ions present in a solution of weak acid. As a result, a weak acid will be poor conductor of electricity.

As electricity is the flow of ions.

Thus, we can conclude that weak acids are poor conductors of electricity.

3 0

4 years ago

1. How many molecules of S2 gas are in 756.2 L?

AfilCa [17]

Answer: There are $2.032 \times 10^{25}$ molecules $S_{2}$ gas are in 756.2 L.

Explanation:

It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of moles present in 756.2 L are calculated as follows.

$Mole = \frac{Volume}{22.4 L}\\= \frac{756.2 L}{22.4 L}\\= 33.76 mol$

According to mole concept, 1 mole of every substance contains $6.022 \times 10^{23}$ molecules.

Therefore, molecules of S present in 33.76 moles are calculated as follows.

$1 mol = 6.022 \times 10^{23}\\33.76 mol = 33.76 \times 6.022 \times 10^{23}\\= 2.032 \times 10^{25}$

Thus, we can conclude that there are $2.032 \times 10^{25}$ molecules $S_{2}$ gas are in 756.2 L.

5 0

3 years ago

Which one would be the correct amswer

Sav [38]

I'm pretty sure it's E also I rarely ever see an e option for answers lol

7 0

4 years ago

A sample of methane occupies a volume of 174.0 mL at 25 C and exerts a pressure of 1030.0 mmHg if the volume of the gas is allow

PolarNik [594]

Answer:

The pressure will be 0,37 atm.

Explanation:

We use the Boyle Mariotte´s formula,where for a given mass of gas, at constant temperature, the pressure and temperature vary inversely proportionally. We see here that the initial and final temperature does not vary (298K).

We convert the unit Celsius into Kelvin (0 ° C = 273K) and the unite mmHg into atm (760mmHg=1 atm):

25°C= 25+273=298K ; (1060mmHgx 1 atm)/760mmHg)=1,39 atm.

We convert unit of volume from ml to L: 174/1000=0,174L and 650/1000=0,650L

P1xV1= P2xV2

1,39 atm x 0,174L =P2 x0,650L

P2= (1,39 atm x 0,174L)/0,650L= 0,37 atm

4 0

4 years ago

Read 2 more answers

What mass of CO2 would be generated along with 35.00g of NaCl?

Sunny_sXe [5.5K]

Answer: The quantitative interpretation of the reaction is as follows: 84.01 g (1 mol) of sodium

bicarbonate reacts with 36.46 g (1 mol) of hydrochloric acid to generate 58.44 g (1 mol) of salt,

18.02 g (1 mol) of water, and 44.01 g (or 1 mol) of carbon dioxide. Of course the starting

quantity of NaHCO3 may be more or less than 84.01 g, but a proportionate quantity of the

hydrochloric acid will be consumed, and proportionate quantities of the products will be formed.

For example, should 100.00 g of NaHCO3 react with excess acid, the theoretical mass of salt

produced would be calculated as follows:

58.44 g sodium chloride 100.00 g sodium bicarbonate

84.01 g sodium bicarbonate = 69.55 g sodium

chloride

Note that when a bicarbonate is reacted with excess acid, the salt produced is the only substance

not readily volatile. That is, the unreacted acid, the water, and the carbon dioxide are easily

removed by heating. Does this help?

3 0

3 years ago