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sergejj [24]
3 years ago
8

If f (x) = StartRoot x minus 3 EndRoot, which inequality can be used to find the domain of f(x)?

Mathematics
1 answer:
Ann [662]3 years ago
4 0

Answer:

x\geq 3 is the inequality to find the Domain of f(x)

Step-by-step explanation:

When we have a function where the variable "x" is inside a square root, we find its Domain by looking for all those values x for which the function is defined for the root, which means all the x-values that make the expression inside the root larger than or equal to zero, avoiding the values smaller for which the square root is not defined.

Therefore, in this case , for

f(x)=\sqrt{x-3}

we ask for the x-values that verify:

x-3\geq 0\\x\geq 3

where we have isolated x on one side of the equal sign.

This would be the definition of the Domain of the function.

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What is 0.19 as a fracton
Lorico [155]

Answer:

u can make it a fraction

Step-by-step explanation:

6 0
3 years ago
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At the peak of a roller coaster ride, the rider's watch flew off his wrist. The height h in feet of the watch, t seconds after h
defon

Answer:

3 \: s

Step-by-step explanation:

y =  - 16 {x}^{2}  + 32x + 48 \\ 0 =  \frac{ - 16 {x}^{2} + 32x + 48 }{ - 16}  \\0  =  {x}^{2}   - 2x - 3 \\   0= {x}^{2}  - 3x + x - 3 \\  0= x(x - 3)  + 1(x - 3) \\0  = (x + 1)(x - 3) \\  \\ x + 1 = 0  \\ x =  - 1 \\ x - 3 = 0 \\ x = 3

Hope this helps you.

<em>Can</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>brainliest</em><em> </em><em>please</em><em>?</em>

6 0
3 years ago
Read 2 more answers
Riangle XYZ was dilated by a scale factor of 2 to create triangle ACB and sin ∠X = 5 over 5 and 59 hundredths.
DochEvi [55]

Answer:

Step-by-step explanation:

1. Part A: We know parts of our triangle since the cosine of X is given.  XY = 2.5 and XZ = 5.59 and since it is a scale factor of 2, ABC is most likely similar to XYZ by angle measures and the special relationship is, that they are all equal, because with a scale factor of two, all the ratios in triangle ABC will simplify to the ratios of triangle XYZ. 

Part B: Because triangle XYZ was dilated with a scale factor of 2 to create triangle ABC, just multiply the sides by 2 to get the sides AC and CB, which is AB = 2 times XY and CB = 2 times XZ. 

2. We can first find the hypothenuse by adding squaring 8 and 6 to have 100. Then square root it to have 10 as our hypothenuse

Now we can use sin x = 6/10 and cos y = 6/10

3. Since this is using the angle of elevation, we can say that the length of side AB is perpendicular from the perspective of angle of elevation, and the hypotenuse's length is known, so in this case, we can use a sine or cosecant ratio. 

Sin(40 Degrees) = AB/100

AB = 100 x sin(40 Degrees) ft

AB ~ 64.28 ft which can be rounded to 64 ft

The triangle I drew was a right triangle with points A, B, and C. 40 is on point C while 100 ft was on the hypotenuse. The kite was near A and the ground was between segment B and C.

4. Since the angle and Adjacent line is given and it is asking us to find H which is the opposite, we well try and be using Tangent = opposite/adjacent 

500 ft Multiply by tan39 = 405 (Estimated after rounding to nearest hundreth 404.892).

To be honest, I didn't know so much about these questions but this might give a better understanding and if I'm wrong then I apologize.

7 0
2 years ago
40% of what number is 84?
Fynjy0 [20]

Answer:

210

Step-by-step explanation:

84 / .40 = 210

(to check)

210 X .40 = 84

4 0
3 years ago
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Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi
notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

z=\frac{x-\mu}{\sigma}

z=\frac{68-74}{6}

z=\frac{-6}{6}=-1

Now let us find z-score for 86.

z=\frac{86-74}{6}    

z=\frac{12}{6}=2        

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,    

P(-1

P(2>Z)=.97725  

We will use formula P(a to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

P(-1

P(-1

Upon converting 0.81859 to percentage we will get

0.81859*100=81.859\approx 81.86

Therefore, 81.86% of final exam score will be between 68 and 86.  


3 0
3 years ago
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