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sergejj [24]
3 years ago
8

If f (x) = StartRoot x minus 3 EndRoot, which inequality can be used to find the domain of f(x)?

Mathematics
1 answer:
Ann [662]3 years ago
4 0

Answer:

x\geq 3 is the inequality to find the Domain of f(x)

Step-by-step explanation:

When we have a function where the variable "x" is inside a square root, we find its Domain by looking for all those values x for which the function is defined for the root, which means all the x-values that make the expression inside the root larger than or equal to zero, avoiding the values smaller for which the square root is not defined.

Therefore, in this case , for

f(x)=\sqrt{x-3}

we ask for the x-values that verify:

x-3\geq 0\\x\geq 3

where we have isolated x on one side of the equal sign.

This would be the definition of the Domain of the function.

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How to do (x-355)+(x)+(80+2x)=2425
sweet-ann [11.9K]

Answer:

  x = 675

Step-by-step explanation:

Collect terms and solve the resulting 2-step linear equation.

  (x-355)+(x)+(80+2x)=2425 . . . . . given

  4x -275 = 2425 . . . simplify

  4x = 2700 . . . . . . . add 275

  x = 675 . . . . . . . . . divide by 4

8 0
2 years ago
X + 2y = 5
malfutka [58]
C.) 5 is the value of X and the value of Y is 5/2
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2 years ago
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A company finds that the rate at which the quantity of a product that consumers demand changes with respect to price is given by
d1i1m1o1n [39]

Answer:

q =  5000/x  + 6

Step-by-step explanation:

D´= dq/dx  =  - 5000/x²

dq = -( 5000/x²)*dx

Integrating on both sides of the equation we get:

q = -5000*∫ 1/x²) *dx

q = 5000/x + K   in this equation x is the price per unit and q demanded quantity and K integration constant

If when  1006 units are demanded when the rice is 5 then

x = 5     and   q = 1006

1006  =  5000/5 +K

1006 - 1000 = K

K = 6

Then the demand function is:

q =  5000/x  + 6

3 0
2 years ago
How do u say 12.87 time as a fractional number
Katarina [22]
If you are talking about a mixed number it would be 12 87/100 if you mean a fraction it is 1287/100
7 0
3 years ago
An engineer measured the Brinell hardness of 25 pieces of ductile iron from her company, that were subcritically annealed. She b
Mrrafil [7]

Answer:

Yes. The sample size is large enough

H0: μ=170

Ha: μ≠ 170

a) μ= 172.52

b) 10.31

c) yes, the data is distributed around both sides of the mean

d) H0: μ=170 is true

Step-by-step explanation:

a) mean= sum of all sample values/25

            (170+167+174+179+179+187+179+183+179 +156+163+156+187+156+167+156+174+170+ 183+ 179+ 174+ 179+ 170+ 159+ 187)/25 = 172.52

b) standard deviation= √(∑(x-μ)²/25)

     Using this formula value of standard deviation was computed to be 10.31

c) Least value is 156, difference between least and mean is 16.52

   Max value is 187, difference between max and mean is 14.48

   A scatter plot shows that number of values higher than mean is 14 and number of values lower than mean is 11. So we can say that data is distributed around mean

d) Null hypthesis is accepted

Test statistic= (sample mean-expected mean)/standard deviation

                  =(172.52-170)/10.31

                   = 0.024

P(Z> 0.024)= (1-0.5080)= 0.492

p-value= 2× 0.492= 0.984

Using 5% or 0.05 significance level,  

test statistic is greater than significance level so null hypothesis is accepted

8 0
2 years ago
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