The balanced equation
2Na₃PO₄+3Ca(NO₃)₂⇒6NaNO₃+Ca₃(PO₄)₂
<h3>Further explanation</h3>
Given
Reaction
_Na3PO4+_Ca(NO3)2-->_NaNO3+_Ca3(PO4)2
Required
Balanced equation
Solution
Give a coefficient
aNa₃PO₄+bCa(NO₃)₂⇒cNaNO₃+Ca₃(PO₄)₂
Ca, left=b, right = 3⇒ b=3
P, left=a, right = 2⇒a=2
Na, left=3a, right=c⇒3a=c⇒3.2=c⇒c=6
The equation becomes :
2Na₃PO₄+3Ca(NO₃)₂⇒6NaNO₃+Ca₃(PO₄)₂
A would be the answer to this question
Answer:
1.0M HCl is the concentration of the acid
Explanation:
Based on the reaction, 1 mole of NaOH reacts per mole of HCl. That means the moles added of NaOH in the neutralization = Moles of HCl in the solution. With the moles and the volume in Liters we can find the molar concentration of HCl
<em>Moles NaOH = Moles HCl:</em>
25.0mL = 0.025L * (2.0moles / L) = 0.050moles HCl
<em>Molarity:</em>
0.050moles HCl / 0.0500L =
<h3>1.0M HCl is the concentration of the acid</h3>
Answer:
The answer is supposed to be "Electron cloud" or "Electon".
