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mel-nik [20]
3 years ago
10

What is the molar mass of KOH?

Chemistry
1 answer:
Julli [10]3 years ago
5 0
<h3>Answer:</h3>

56.11 g/mol

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Compound] KOH

<u>Step 2: Identify</u>

[PT] Molar Mass of K - 39.10 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

<u>Step 3: Find</u>

39.10 + 16.00 + 1.01 = 56.11 g/mol

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3. At STP, how many liters of oxygen gas are required to react completely with 3.2 x 10^22
Mrrafil [7]

The volume of oxygen required to react with 3.2 * 10²² molecules of hydrogen is 0.56 L.

<h3>What is stoichiometric law?</h3>

The stoichiometric law has been given as the representation of the moles of product and reactant in a chemical reaction are represented by the stoichiometric coefficient.

It has been known that 1 mole of a compound has 6.023 * 10²³ molecules. Thus, the moles of hydrogen gas equivalent to 3.2 * 10²² molecules has been:

6.023 * 10²³ molecules = 1 mole

3.2 * 10²² molecules = 1/6.023 * 10²³ * 3.2 * 10²² moles

3.2 * 10²²  molecules = 0.05 moles

Thus, the moles of hydrogen gas available is 0.05 moles.

From the stoichiometric law, according to the balanced chemical equation,

2 moles of hydrogen requires = 1 moles of oxygen

0.05 moles of hydrogen requires = 1/2 * 0.05 moles oxygen

0.05 moles of hydrogen requires =  0.025 moles oxygen

Thus, the moles of oxygen required is 0.025 moles. At STP, a mole of gas been equivalent to 22.4 L . Thus, the volume of 0.025 moles oxygen has been:

1 mole = 22.4 L

0.025 moles = 22.4 * 0.025 L

0.025 mole = 0.56 L

Thus, the volume of oxygen required to react with 3.2 * 10²² molecules of hydrogen is 0.56 L.

Learn more about stoichiometric law, here:

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7 0
2 years ago
How did the surface area of the metal strip expose to the solution affect the
frez [133]

Answer:

See explanation below

Explanation:

In an electrochemical cell, electricity is obtained by the gradual deterioration of the anode.

Hence, surface area of the metal will affect the length of time within which the electrochemical cell works.

The greater the surface area of the metal, the longer the electrochemical cell can function and the greater the quantity of electricity produced, hence the answer above.

3 0
3 years ago
Im sooooooooooooooooooooooooo cufused on science
Elena-2011 [213]

Answer:

What do you need please to understand?

6 0
3 years ago
Please I need help with questions 1-4 and can you check if I plot it correct in to the punnet square for questions 1-4 and I nee
fgiga [73]
Number 1 is incorrect, the genotypes are given to you. You need to use GG and gg. The outcome would be 100% Gg.

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Number 4 is incorrect, the genotypes are given to you. You need to use RR and rr. The outcome would be 100% Rr.

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8 0
3 years ago
Calculate the ph of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions.
Makovka662 [10]

The pH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions is 13.5.

<h3>What is pH? </h3>

pH is defined as the concentration of the hydrogen bond which is released or gained by the species in the solution which depicts the acidity and basicity of the solution.

<h3>What is pOH? </h3>

pOH is defined as the concentration of the hydronium ion present in solution.

pOH value is inversely proportional to the value of pH.

pH value increases, pOH value decreases and vice versa.

Given,

Total H+ ions = 2.95 ×10^(-12)M

<h3>Calculation of pH</h3>

pH = -log[H+]

By substituting the value of H+ ion in given equation

= log(2.95× 10^(-12) )

= 13.5

Thus we find that the pH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions is 13.5.

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8 0
2 years ago
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