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julia-pushkina [17]
3 years ago
15

The average induced emf will be given by the time rate of change and the product of the and the .

Physics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0
<span>The average induced emf will be given by the time rate of change and the product of the number of coils and the rate of change of magnetic field</span>
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How many paths through which charge can flow would be shown in the circuit diagram of a series circuit?
Natalka [10]

A) one ... same current passes through each cpt


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3 years ago
A kayakeris paddling 2.50 m/s at an angle of 45° (northeast) and the current is moving 1.25 m/s at an angle of 315° (southeast).
PIT_PIT [208]

The kayaker has velocity vector

<em>v</em> = (2.50 m/s) (cos(45º) <em>i</em> + sin(45º) <em>j</em> )

<em>v</em> ≈ (1.77 m/s) (<em>i</em> + <em>j</em> )

and the current has velocity vector

<em>w</em> = (1.25 m/s) (cos(315º) <em>i</em> + sin(315º) <em>j</em> )

<em>w</em> ≈ (0.884 m/s) (<em>i</em> - <em>j</em> )

The kayaker's total velocity is the sum of these:

<em>v</em> + <em>w</em> ≈ (2.65 m/s) <em>i</em> + (0.884 m/s) <em>j</em>

That is, the kayaker has a velocity of about ||<em>v</em> + <em>w</em>|| ≈ 2.80 m/s in a direction <em>θ</em> such that

tan(<em>θ</em>) = (0.884 m/s) / (2.65 m/s)   →   <em>θ</em> ≈ 18.4º

or about 18.4º north of east.

5 0
3 years ago
Which objects have both potential and kinetic energy? Check all that apply.
wariber [46]
A falling raindrop
Kinetic energy and potential energy are both applied when a body or object is falling.
3 0
3 years ago
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A railroad track and a road cross at right angle. An observer stands on the road 70 meters south of the crossing and watches an
fgiga [73]

Answer:

The train is moving with a speed of 57.6 m/s.    

Explanation:

Given that,

Distance of observer from the road, d = 40 m (due south)

Velocity of the train, v = 60 m/s (due east)

So,

x(t)=70\\\\y(t)=60t

t is time

Net displacement is given by :

z(t)=\sqrt{(60t)^2+(70)^2}

Differentiating above equation wrt t as :

z'(t)=\dfrac{1}{2}(3600t^2+4900)^{-1/2}{\cdot} 7200t

Put t = 4 s

z'(4)=\dfrac{1}{2}(3600(4)^2+4900)^{-1/2}{\cdot} 7200(4)\\\\z'(4)=57.6\ m

So, the train is moving with a speed of 57.6 m/s.    

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During photosynthesis *
Lady_Fox [76]

Answer:

<em>converted</em>

Explanation:

into chemical

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