Answer:
Mass is the correct answer.
Explanation:
Many drivers report a more positive handling response and a definite improvement when reducing unsprung mass. You want to keep unsprung weight to as little as possible. This minimizes the momentum and energies that your suspension has to counter. In effect, it can make your shocks more sensitive.
Answer:
Explanation:
For this interesting problem, we use the definition of centripetal acceleration
a = v² / r
angular and linear velocity are related
v = w r
we substitute
a = w² r
the rectangular body rotates at an angular velocity w
We locate the points, unfortunately the diagram is not shown. In this case we have the axis of rotation in a corner, called O, in one of the adjacent corners we call it A and the opposite corner A
the distance OB = L₂
the distance AB = L₁
the sides of the rectangle
It is indicated that the acceleration in in A and B are related
we substitute the value of the acceleration
w² r_A = n r_B
the distance from the each corner is
r_B = L₂
r_A =
we substitute
\sqrt{L_1^2 + L_2^2} = n L₂
L₁² + L₂² = n² L₂²
L₁² = (n²-1) L₂²
0.05*0.2=0.05*0.15+0.015*m2',
m2'=1/6 m/s,
m2'=0.17 m/s
N I C E - D A Y!
Definition: Momentum = (mass) x (speed)
OK. Here we go.
Watch closely:
Divide each side
by 'mass' : <span>Momentum / mass = Speed </span>
Did you follow that ?
Volume = mass / density
Volume = 20 / 7.87
Volume = 2.54 (2 s.f)