<em>The cd's moment of inertia for rotation about a perpendicular axis through its center is about </em><em>5.3 × 10⁻⁵ kg.m²</em>

<h3>Further explanation</h3>
<em>Let's recall </em><em>Angular Momentum</em><em> and </em><em>Moment of Inertia of Cylinder</em><em> formula as follows:</em>

<em>where:</em>
<em>L = angular momentum ( kg.m²/s )</em>
<em>I = moment of inertia ( kg.m² )</em>
<em>ω = angular frequency ( rad/s )</em>


<em>where:</em>
<em>I = moment of inertia ( kg.m² )</em>
<em>M = mass of object ( kg )</em>
<em>R = radius of object ( m )</em>

<u>Given:</u>
mass of cd = M = 25 g = 0.025 kg
diameter of cd = d = 13 cm = 0.13 m
radius of cd = R = d/2 = 0.13/2 = 0.065 m
<u>Asked:</u>
moment of inertia = I = ?
<u>Solution:</u>




<h3>Learn more</h3>

<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Circular Motion