Coil the wire around the nail. Connect one end of the wire to the positive battery terminal. Connect the other end of the wire t
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The equation (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.
The horizontal momentum is given by:
Where:
- m₁: is the mass of the lab cart = 15 kg
- m₂: is the <em>mass </em>of the object dropped = 2 kg
: is the initial velocity of the<em> lab cart </em>
: is the <em>initial velocit</em>y of the <em>object </em>= 0 (it is dropped)
: is the final velocity of the<em> lab cart </em>
: is the <em>final velocity</em> of the <em>object </em>
Then, the horizontal momentum is:
When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:
Therefore, the equation represents the horizontal momentum (option 3).
Learn more about linear momentum here:
I hope it helps you!
De broglie wavelength, , where h is the Planck's constant, m is the mass and v is the velocity.
Mass of hydrogen atom,
v = 440 m/s
Substituting
Wavelength
So the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm