Answer:
392 kJ
Explanation:
Given that,
The total mass of the cabin and the passengers = 800 kg
The vertical distance between B and C is 50 m.
We need to find the increase of gravitational potential energy of the cabin and passengers when they move from B to C. It can be given by the relation as follows :
So, the increase in gravitational potential energy is 392 kJ.
Answer:
= -12 N
, = -80 N and = - 44 N
Explanation:
The force is related to the potential energy by the formula
F = -Δ U = - ( i ^ + j ^ + k ^)
It indicates the potential energy
U = 2xyz + 3z² + 4yx + 16
To solve this problem let's make the derivatives, to find each component of the force
= 2yz + 0 + 4y + 0 = 2yz + 4y
= 2xz + 0 + 4x + 0 = 2xz + 4x
= 2xy + 3 2z + 0 +0 = 2xy + 6z
We look for the expression for the force in each axis
= - 2yz - 4y
= -2xz -4x
= -2xy -6z
We calculate at the point P = (20 i ^ + 1j ^ + 4 k ^) m
= - 2 1 4 - 4 1
= -12 N
= - 2 20 4 - 4 20
= -80 N
= - 20 1 - 6 4
= - 44 N
We put together the expression for strength
F = (-12 i ^ - 80j ^ -44k ^) N
<h2>
Distance traveled in 1 second after drop is 4.9 m</h2><h2>
Distance traveled in 4 seconds after drop is 78.4 m</h2>
Explanation:
We have s = ut + 0.5at²
For a free falling object initial velocity u = 0 m/s and acceleration due to gravity, g = 9.8 m/s²
Substituting
s = 0 x t + 0.5 x 9.8 x t²
s = 4.9t²
We need to find distance traveled in 1 s and 4 s
Distance traveled in 1 second
s = 4.9 x 1² = 4.9 m
Distance traveled in 4 seconds
s = 4.9 x 4² = 78.4 m
Distance traveled in 1 second after drop = 4.9 m
Distance traveled in 4 seconds after drop = 78.4 m
Try looking up the lesson and book name on the internet. then put "answer sheet"
Sonogram is a device that transmit high frequencies to project certain images (ultrasound) , while on the other hand, frequency spectrum uses certain frequencies to transmit data or information ( radio, cellphone).
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