2. 3000. kg car is moving across level ground at 5.0 m/s when it begins an
1 answer:
You might be interested in
Answer:
The correct answer to the question is (A)
When it hits the heavy rope, compared to the wave on the string, the wave that propagates along the rope has the same (A) frequency
Explanation:
The speed of a wave in a string is dependent on the square root of the tension ad inversely proportional to the square root of the linear density of the string. Generally, the speed of a wave through a spring is dependent on the elastic and inertia properties of the string
Therefore if the linear density of the heavy rope is four times that of light rope the velocity is halved and since
v = f×λ therefore v/2 = f×λ/2
Therefore the wavelength is halved, however the frequency remains the same as continuity requires the frequency of the incident pulse vibration to be transmitted to the denser medium for the wave to continue as the wave is due to vibrating particles from a source for example
Answer:
V = 0.39 m/s
Explanation:
Given that,
Mass of hockey puck, m = 0.2 kg
Mass of goalie = 40 kg
Speed of hockey puck, v = 80 m/s
We need to find the speed with which the goalie slide on the slide. Let V be the speed. Using the conservation of momentum as follows :
So, the required speed is 0.39 m/s.
Answer:
The appropriate response will be "Length must be increased by 0.012%".
Explanation:
The given values is:
ΔT = 5 s/day
Now,
⇒
On multiplying both sides by "100", we get
⇒
⇒ (%)
∵
On substituting the values, we get
⇒ % =
%
On applying cross multiplication, we get
⇒ % =
%
⇒ =
⇒ =
⇒ = %