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VladimirAG [237]
3 years ago
11

2. 3000. kg car is moving across level ground at 5.0 m/s when it begins an

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

yes

Explanation: Work is done when there is movement. Therefore it was work was being done.

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Thomas and Lilian are walking down the street to get to the corner store. They walk 5 blocks up the street and turn right by the
vfiekz [6]

Answer:

Thomas is correct that the zero displacements

Lilian is right that the distance is greater than zero.

Explanation:

In this problem we have to be clear about the difference between displacement and distance.

The displacement is a vector, that is, it has a modulation and direction, in this case we can draw a vector for the outward trip and another vector for the return trip, both will have the same magnitude, but their directions are opposite, so the resulting vector is zero.

The distance is a scalar and its value coincides with the modulus of the distance vector, in our case the distance is d for the outward journey and d for the return journey, so the total distance is 2d, which is different from zero.

The two students have some reason, but neither complete,

The displacement is zero because it is a vector and

the distance is different from zero (2d) because it is a scalar

 

Thomas is correct that the zero displacements

Lilian is right that the distance is greater than zero.

Therefore I agree with both, because each one has a 50% of the reason

4 0
3 years ago
Phyics again , pls and thank you!
Alika [10]

Answer: accelerating/ speeding up

Explanation: since it is rising constantly and keeps getting higher it is increasing

3 0
3 years ago
Read 2 more answers
Why not two magnetic field lines can intersect? why not it is possible?
11111nata11111 [884]
At each point on a 'line', the direction of the 'line' is the direction of the force
on a small test magnet placed in the field at that point.

If two 'lines' crossed at the same point, that means a small test magnet placed
at that point in the field would feel a force in two different directions.

But even if that were true, then the net effect on the small test magnet would be
the vector sum of the two forces, and they would be represented by a single net
force anyway, and therefore by a single field 'line' at that point.
4 0
4 years ago
Using the midpoint and the distance formulas, calculate he coordinate of the midpoint and the length of the segment.
arsen [322]

Answer:

Explanation:

Formula to calculate the distance between two points (x_1,y_1) and (x_2,y_2) is,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Therefore, length of CD having coordinates C(3,1) and D(3, 3),

CD = \sqrt{(3-3)^2+(1-3)^2}

     = 2 units

Formula to find the midpoint of CD is,

M = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

   = (\frac{3+3}{2},\frac{1+3}{2})

   = (3, 2)

Therefore, length of CD = 2 units and (3, 2) are the coordinates of the midpoint of CD.

7 0
4 years ago
A que profundidad esta nadando una persona dentro de una alberca si la presión absoluta sobre ésta es de 156kPa?
lara31 [8.8K]

Answer:

La persona está nadando en la alberca a una profundida de 5.575 metros.

Explanation:

La presión absoluta (P_{tot}) experimentada por la persona es la suma de la presión atmosférica (P_{atm}) y la presión hidrostática de la columna de agua de la alberca (P_{h}), medidas en kilopascales. Es decir,

P_{tot} = P_{atm}+P_{h} (1)

P_{tot} = P_{atm} + \frac{\rho\cdot g \cdot z}{1000} (2)

Donde:

\rho - Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

z - Profundidad de la persona en la alberca, medida en metros.

Si sabemos que P_{atm} = 101.325\,kPa, \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} y P_{tot} = 156\,kPa, entonces la profundidad de la persona en la alberca es:

156 = 101.325 +\frac{(1000)\cdot (9.807)\cdot z}{1000}

54.675 = 9.807\cdot z

z = 5.575\,m

La persona está nadando en la alberca a una profundida de 5.575 metros.

5 0
3 years ago
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