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gtnhenbr [62]
3 years ago
12

In laboratory experiment, a NOVDEC Student was

Chemistry
1 answer:
Ede4ka [16]3 years ago
3 0

Answer:

i. Molar mass of glucose = 180 g/mol

ii. Amount of glucose = 0.5 mole

Explanation:

<em>The volume of the glucose solution to be prepared</em> = 500 cm^3

<em>Molarity of the glucose solution to be prepared</em> = 1 M

i. Molar mass of glucose (C_1_2H_6O_6) = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol

ii.<em> mole = molarity x volume</em>. Hence;

amount (in moles) of the glucose solution to be prepared

                 = 1 x 500/1000 = 0.5 mole

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