X2 + y2 - 14x + 10y = 250
x2 -14x + 49 - 49 + y2 + 10x + 25 - 25 = 250
(x - 7)^2 - 49 + (y+5)^2 - 25 = 250
(x-7)^2 + (y+5)^2 = 250 + 49 + 25
(x-7)^2 + (y+5)^2 = 324
Therefore the radius, r
r = 324^0.5
r = 18
The area of a square is
s • s
We can also write this as
s^2
So, for any side length “s”, we can make a function, A(s), such that
A(s) = s^2
Now that we have a quadratic equation for the area of a square, let’s go ahead and solve for the side lengths of a square with a given area. In this case, 225 in^2
225 = s^2
Therefore,
s = sqrt(225)
s = 15
So, the dimensions are 15 x 15 in
It looks like your equations are
7M - 2t = -30
5t - 12M = 115
<u>Solving by substitution</u>
Solve either equation for one variable. For example,
7M - 2t = -30 ⇒ t = (7M + 30)/2
Substitute this into the other equation and solve for M.
5 × (7M + 30)/2 - 12M = 115
5 (7M + 30) - 24M = 230
35M + 150 - 24M = 230
11M = 80
M = 80/11
Now solve for t.
t = (7 × (80/11) + 30)/2
t = (560/11 + 30)/2
t = (890/11)/2
t = 445/11
<u>Solving by elimination</u>
Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,
7M - 2t = -30 ⇒ -10t + 35M = -150 … (multiply by 5)
5t - 12M = 115 ⇒ 10t - 24M = 230 … (multiply by 2)
Now combining the equations eliminates the t terms, and
(-10t + 35M) + (10t - 24M) = -150 + 230
11M = 80
M = 80/11
It follows that
7 × (80/11) - 2t = -30
560/11 - 2t = -30
2t = 890/11
t = 445/11
Answer:
Simple
Step-by-step explanation:
Remove cables from battery terminals. ...
Remove the screws or fasteners holding the battery in place; then Remove the Battery. ...
Inspect the tray the old battery was resting on. ...
Position your new car battery on the tray. ...
Replace the screws/fasteners to the new battery to secure it in place.
Step 6. Reconnect your battery cables in the reverse order in which you took them off
Answer:
the total are is 459
Step-by-step explanation:
3 3/16 divided by 1/8 = 25 1/2 or 25.5
2 1/4 divided by 1/8 = 18
so 18 x 25.5 = 459
hope this helps
