Answer:
a) The strength of gravity decreases if one moved away from Jupiter
b) The strength of gravity increases if one fell into Jupiter
Explanation:
The gravitational attraction is given by Newton law of gravitation as follows;
![Force \ (strength) \ of \ gravity = \dfrac{G \times M \times m}{R^2}](https://tex.z-dn.net/?f=Force%20%5C%20%28strength%29%20%5C%20of%20%5C%20gravity%20%3D%20%5Cdfrac%7BG%20%5Ctimes%20M%20%5Ctimes%20m%7D%7BR%5E2%7D)
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)
M = The mass of Jupiter
m = The mass of the nearby body
R = The distance between the centers of Jupiter and the body
From the equation, we have that the gravitational strength varies inversely with the square of the separation distance between two bodies
Therefore, as one moves away, R increases, and the strength of gravity reduces
Similarly as the body falls into Jupiter, R, reduces the gravitational strength increases.
Answer: Find the answer in the explanation
Explanation: Given the Roman numeral and the representation
I. part of a coal-fired power plant
II. part of a nuclear power plant
III. part of a coal-fired power plant and part of a nuclear power plant
a.) Boiler : I
b.) Combustion chamber: I
c.) Condenser: I
d.) Control rod: II
e.) Generator: III
f.) Turbine: III
Toward the end processes part of both coal fire and nuclear power, they both make use of turbine and generator to generate electricity.
Answer:
f = 931.1 Hz
Explanation:
Given,
Mass of the wire, m = 0.325 g
Length of the stretch, L = 57.7 cm = 0.577 m
Tension in the wire, T = 650 N
Frequency for the first harmonic = ?
we know,
![v =\sqrt{\dfrac{T}{\mu}}](https://tex.z-dn.net/?f=v%20%3D%5Csqrt%7B%5Cdfrac%7BT%7D%7B%5Cmu%7D%7D)
μ is the mass per unit length
μ = 0.325 x 10⁻³/ 0.577
μ = 0.563 x 10⁻³ Kg/m
now,
![v =\sqrt{\dfrac{650}{0.563\times 10^{-3}}}](https://tex.z-dn.net/?f=v%20%3D%5Csqrt%7B%5Cdfrac%7B650%7D%7B0.563%5Ctimes%2010%5E%7B-3%7D%7D%7D)
v = 1074.49 m/s
The wire is fixed at both ends. Nodes occur at fixed ends.
For First harmonic when there is a node at each end and the longest possible wavelength will have condition
λ=2 L
λ=2 x 0.577 = 1.154 m
we now,
v = f λ
![f = \dfrac{v}{\lambda}](https://tex.z-dn.net/?f=f%20%3D%20%5Cdfrac%7Bv%7D%7B%5Clambda%7D)
![f = \dfrac{1074.49}{1.154}](https://tex.z-dn.net/?f=f%20%3D%20%5Cdfrac%7B1074.49%7D%7B1.154%7D)
f = 931.1 Hz
The frequency for first harmonic is equal to f = 931.1 Hz
Answer:
in a magnet there is a magnetic field that draws ever mental to it