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3 years ago

13

You performed an experiment in which you measured the amount of water leaking through different types of roofs. For one roof, yo

u measured a volume of 13.2 ounces. What is this measurement in SI units? 1 lb oz; 1 kg =2.2 lbs.

2 answers:

Ostrovityanka [42]3 years ago

6 0

Given:
m = 13.2 oz, the mass of water measured

Note that
$1 \, oz = (1 \, oz)*( \frac{1}{16} \, \frac{lb}{oz} )*( \frac{1}{2.2} \, \frac{kg}{lb} ) = 0.0284 \, kg$

Answer: 0.0284 kg

Verizon [17]3 years ago

6 0

Answer:

.375

Explanation:

I was taking the quiz and got it right

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One block rests upon a horizontal surface. A second identical block rests upon the first one. The coefficient of static friction

goblinko [34]

Answer:

The magnitud of the force is 124.8N.

Explanation:

First we have to find the value of the static friction coefficient, when the external force F is applied to upper block (i will call it A Block) we have a free body diagram as the one shown in the figure i attached, so since this block has no aceleration in any direction the force F should be equal to the friction force between A and B block, one we noticed this we can use the equation for the Friction force to find the coefficient:

$0=F-FrictionAB$

$F=FrictionAB=Nab*$ μs

and again, since the block has no acceleration the normal between A and B block should be equal to the weigth of the first block, so we have:

$0=Nab-W$

$Nab=W=mg$

replacing this we have:

$F=$ μs $*Nab=$ μs* $mg=41.6N$

and μs $=41.6N/(mg)$

now it's time to see the free body diagram for the b block, if we now apply the F force to the B block the diagram should look like in the figure.

the color of the arrow gives you an idea of where the force comes from, the blue ones comes from the B block, the red ones from the A block and the brown ones from the ground.

now for the B block you can see two friction forces, one for the ground and one for the A block, both of these directed bacwards, and two normal forces, again one for the ground and one for the A block but the normal force for the A block is aiming downwards.

again we use the fact that the block is not accelerating in any direction so the sum of the forces in x and y direction have to be 0, so:

$F-Friction1(ground)-Friction2(AB)=0$

This is the new external F force that we are looking for:

$F=Friction1(ground)+Friction2(AB)$

we know Friction2(AB) because we found that in the previous block so:

$F=Friction1(ground)+mg$ *μs

for the other friction we have to use the equation:

$Friction(ground)=N(ground)$ *μs

from y axis we have:

$N(ground)-w-Normal(AB)=0$

$N(ground)=w+Normal(AB)$

we found the value of Normal(AB) with the previous block so:

$N(ground)=mg+mg=2mg$

and:

$Friction(ground)=2mg$ *μs

$F=Friction(ground)+mg$ *μs

$F=2mg$ *μs+μs* $mg=3mg$ *μs

and since: μs* $mg=41.6N$

the new F force would be:

$F=3mg$ *μs $=41.6*3=124.8N$

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3 years ago

7. Navy use SONAR method to locate the position of submarine under water. The waves used in SONAR are A transverse waves. B elec

pshichka [43]

Answer:

A. transverse waves

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Troyanec [42]

Part 1

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Part 2

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Will this one work?...................

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