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cupoosta [38]
3 years ago
6

What type of bonding is represented in Figure 2-2???

Physics
1 answer:
Sindrei [870]3 years ago
6 0
Answer:  "ionic bonding" .
_______________________________________
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Calculate the length of a simple pendulum that oscillates with a frequency of 0.4Hz g=10m/s2 , ^=3.142
earnstyle [38]

Answer:

Explanation:

For simple pendulum the formula is

T=2\pi\sqrt{\frac{l}{g} }

Where T is time period , l is length and g is acceleration due to gravity .

\frac{1}{n} =2\pi\sqrt{\frac{l}{g} }

n is frequency

Putting the values

\frac{1}{.4} =2\pi\sqrt{\frac{l}{10} }

\frac{l}{10} = .1584

l = 1.584 m

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A laser of wavelength 720 nm illuminates a double slit where the separation between the slits is 0.22 mm. Fringes are seen on a
kumpel [21]

Answer:

The appropriate solution is "2.78 mm".

Explanation:

Given:

\lambda = 720 \ nm

or,

  = 720\times 10^{-9} \ m

D=0.85 \ m

d = 0.22 \ mm

or,

  =0.22 \times 10^{-3} \ m

As we know,

Fringe width is:

⇒ \beta=\frac{\lambda D}{d}

hence,

Separation between second and third bright fringes will be:

⇒ \theta=\beta=\frac{\lambda D}{d}

       =\frac{720\times 10^{-9}\times 0.85}{0.22\times 10^{-3}}

       =2.78\times 10^{-3} \ m

or,

       =2.78 \ mm

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