Answer:
Kp and Kc are 0.01266 and 145.17, respectively.
Explanation:
Please check document attached.
The 2 in front of in is <u>Coefficient.</u>
_____________________________
The after in the same equation is <u>sub </u><u>script</u><u>.</u>
_____________________________
There are two atoms of in
_____________________________
<span>4FeS2 + 11O2 = 2Fe2O3 + 8SO2</span>
Percent yield is calculated as the actual yield divided by the theoretical yield multiplied by 100.
Actual yield = 55 g ( 1 mol / 159.69 g ) = 0.34 mol Fe2O3
To find for the theoretical yield, we first determine the limiting reactant.
100 g O2 ( 1 mol / 32 g) = 3.13 mol O2
200 g FeS2 (1 mol / 119.98g) = 1.67 mol FeS2
Therefore, the limiting reactant is O2.
Theoretical yield = 3.13 mol O2 ( 2 mol Fe2O3 / 11 mol O2 ) = 0.57 mol Fe2O3
Percent yield = (0.34 mol / 0.57 mol) x 100 = 59.74%
That would be phosphorus. It’s electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^3