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In-s [12.5K]
3 years ago
11

Light of wavelength 600nm illuminates a diffraction grating. The second-order maximum is at angle 39°. How many lines per millim

eter does this grating have?
Physics
1 answer:
fomenos3 years ago
3 0

Answer:

the number of lines is 526

Explanation:

The wavelength  λ =600nm = 600 × 10⁻⁶ mm

The diffraction angle θ = 39°

Recall the expression for the relation between the wavelength, angle and central maxima distance.

Recall the expression for the relation between the wavelength, angle and central maxima distance.

Recall the expression for the relation between the wavelength, angle and central maxima distance.

relation between the wave length, angle and central maxima distance

d =  nλ / sinθ

Here n = 2 for second order maxima and d is the distance

= 2(600 × 10⁻⁶) / sin 39°

= 1200 × 10⁻⁶ / 0.6293

= 1.9 × 10⁻³ mm

N = 1/d

= 1 / 1.9 × 10⁻³

= 526

The grating has a line density of 526 lines per millimeter

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63.4^{\circ}

Explanation:

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When the (now polarized) light hits the second polarizer, whose axis of polarization is rotated by an angle \theta with respect to the first one, the intensity of the light coming out is

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If we combine (1) and (2) together,

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We want the final intensity to be 1/10 the initial intensity, so

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So we can rewrite (3) as

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Explanation:

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a ) When an electron is stationary in the electric field and magnetic field , he will be affected by electric field but not by magnetic field. Magnetic field can exert force only on mobile charges.

b ) When the electron is moving parallel to electric field and magnetic field . In this case also electric field will  exert force on electron but magnetic field field will not exert force on electrons . Magnetic field can exert force only on the perpendicular component of the velocity of charged particles.

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Un ciclista recorre 10 km en 2 h.Calcula su velocidad media en km/h.¿cuantos metros recorre cada segundo
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La velocidad media relaciona el cambio de la posición con el tiempo empleado en efectuar dicho cambio. Por lo que se calcula como la distancia recorrida por un objeto dividido por el tiempo transcurrido:

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Entonces, reemplazando en la definición de velocidad media:

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Resolviendo se obtiene:

velocidad=5 \frac{km}{h}= 1.389\frac{m}{s}

<u><em>La velocidad media es 5 </em></u>\frac{km}{h}<u><em>, que equivale a 1.389 </em></u>\frac{m}{s}<u><em></em></u>

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