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In-s [12.5K]
3 years ago
11

Light of wavelength 600nm illuminates a diffraction grating. The second-order maximum is at angle 39°. How many lines per millim

eter does this grating have?
Physics
1 answer:
fomenos3 years ago
3 0

Answer:

the number of lines is 526

Explanation:

The wavelength  λ =600nm = 600 × 10⁻⁶ mm

The diffraction angle θ = 39°

Recall the expression for the relation between the wavelength, angle and central maxima distance.

Recall the expression for the relation between the wavelength, angle and central maxima distance.

Recall the expression for the relation between the wavelength, angle and central maxima distance.

relation between the wave length, angle and central maxima distance

d =  nλ / sinθ

Here n = 2 for second order maxima and d is the distance

= 2(600 × 10⁻⁶) / sin 39°

= 1200 × 10⁻⁶ / 0.6293

= 1.9 × 10⁻³ mm

N = 1/d

= 1 / 1.9 × 10⁻³

= 526

The grating has a line density of 526 lines per millimeter

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A motorcycle is moving at 30 m/s when the rider applies the brakes, giving the motorcycle a constant deceleration. During the 3.
shutvik [7]

Answer:

The motorcycle travelled 69.73 m during these 3.1 s.

Explanation:

In order to calculate the distance that the motorcycle travelled we first need to obtain the acceleration rate that was used to brake the vehicle. We do that by using the following formula:

a = (V_final - V_initial)/(t) = (15 - 30)/(3.1) = -4.84 m/s^2

The distance is given by the following formula:

S = (V_final^2 - V_initial^2)/(2*a)

S = (15^2 - 30^2)/[2*(-4.84)] = (225 - 900)/(-9.68) = -675/(-9.68) = 69.73 m

The motorcycle travelled 69.73 m during these 3.1 s.

5 0
3 years ago
State the law of conservation of momentum<br>​
trapecia [35]

Answer:

Law of conservation of momentum states that. For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.

Explanation:

Hope it helps

8 0
3 years ago
Read 2 more answers
A satellite orbits the earth at a speed of 8.0x 10^3m/s . Calculate the period of orbit of the satellite if the distance between
gladu [14]

Hi there!

The period of an orbit can be found by:

T = \frac{2\pi r}{v}

T = Period (? s)
r = radius of orbit (6400000 m)

v = speed of the satellite (8000 m/s)

This is the same as the distance = vt equation. The total distance traveled by the satellite is the circumference of its circular orbit.

Let's plug in what we know and solve.

T = \frac{2\pi (6400000)}{8000} = \boxed{5026.55 s}

8 0
1 year ago
Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.0
e-lub [12.9K]

Answer:

f = 421.8 Hz

Explanation:

When she moved a distance of 1 m from mid point she observe first destructive interference due to two speakers

so we can say that path difference of sound due to two speakers will be equal to half of the wavelength

so path difference is given as

\Delta L = {3.5^2 + 12^2}^{0.5} - {1.5^2 + 12^2}^{0.5}

so it will be

\Delta L = 12.5 - 12.093

\Delta L = 0.4066

now we know that

\frac{\lambda}{2} = 0.4066

\lambda = 0.813

now frequency of sound is given as

f = \frac{v}{\lambda}

f = \frac{343}{0.813}

f = 421.8 Hz

4 0
3 years ago
Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.
o-na [289]

Answer:

Current = 10 Amperes.

Explanation:

Given the following dat;

Quantity of charge, Q = 36 kilocoulombs (KC) = 36 * 1000 = 36000C

Time = 1 hour to seconds = 60*60 = 3600 seconds

To find the current;

Quantity of charge = current * time

Substituting in the equation

36000 = current * 3600

Current = 36000/3600

Current = 10 Amperes.

6 0
3 years ago
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